所以我确实有两个数据数组:
Bx = [ -59.57011259 -74.20675537 -90.53224156 ..., -1676.9703173
-1676.9703173 -1676.9703173 ]
By = [ 1.48413511e+00 4.96417605e+00 8.39303992e+00 ..., -1.67697032e+03
-1.67697032e+03 -1.67697032e+03]
我有一个程序向我展示这些数据,但我需要在Python2.7中完成它。我尝试使用我在本主题(Plotting a Fast Fourier Transform in Python)中找到的代码,但说实话,我对理解FFT有麻烦,你能帮忙吗?
# Number of samples
N = 600
# Sample spacing
T = 300.0 / 266336
x = np.linspace(0.0, N*T, N)
y = np.sin(50.0 * 2.0*np.pi*x) + 0.5*np.sin(80.0 * 2.0*np.pi*x)
yf = fft(y)
xf = np.linspace(0.0, 1.0/(2.0*T), N/2)
plt.plot(xf, 2.0/N * np.abs(yf[0:N/2]))
plt.grid()
plt.show()
有关我的数据的一些信息: 记录/样本数量266336; 时间300s = 300000ms
我还需要以某种方式实施blackman或hamming窗口,你能帮忙吗?
答案 0 :(得分:2)
假设Bx
和By
类似于数组,可以由*
运算符编写窗口。
import numpy as np
import matplotlib.pyplot as plt
# Number of samplepoints
N = 266336
# sample spacing
T = 300.0 / N
# Window
win = np.hamming(N)
x = np.linspace(0.0, N*T, N)
# y = np.sin(50.0 * 2.0*np.pi*x) + 0.5*np.sin(80.0 * 2.0*np.pi*x)
y = np.array(Bx)
y_win = win * y
yf = np.fft.fft(y_win)
xf = np.linspace(0.0, 1.0/(2.0*T), N/2)
# Plot original data
ax = plt.subplot(3,1,1)
ax.grid()
ax.plot(y)
# Plot windowed data
ax = plt.subplot(3,1,2)
ax.grid()
ax.plot(y_win)
# Plot spectrum
ax = plt.subplot(3,1,3)
ax.grid()
ax.plot(xf, 2.0/N * np.abs(yf[:N/2]))
plt.show()
答案 1 :(得分:1)
我使用了Welch方法,这是一个好主意。结束了。问题解决了。
# Loop for FFT data
for dataset in [fft1]:
dataset = np.asarray(dataset)
freqs, psd = welch(dataset, fs=266336/300, window='hamming', nperseg=8192)
plt.semilogy(freqs, psd/dataset.size**2, color='r')
for dataset2 in [fft2]:
dataset2 = np.asarray(dataset2)
freqs2, psd2 = welch(dataset2, fs=266336/300, window='hamming', nperseg=8192)
plt.semilogy(freqs2, psd2/dataset2.size**2, color='b')