Question

我有三列，时间戳（时间戳），超时（时间戳）和员工。我需要获得在特定时间范围内工作的员工数量（间隔30分钟）。例如：

    employee_id              timein              timeout
    101                      10:10               12:59
    102                       9:07               12:16
    103                      11:16               12:08

我需要一个能给我这个结果的查询

    timeframe         count(employee_id)
    09:00                    1
    09:30                    1
    10:00                    2
    10:30                    2
    11:00                    3
    11:30                    3
    12:00                    3
    12:30                    1

我真的希望我说清楚了。感谢

Answer 1

请参阅此演示：http://sqlfiddle.com/#!17/2477f/1

SELECT x.timeframe, count(employee_id)
FROM (
   select time '8:00' + x * interval '30 minute' as timeframe,
          time '8:00' + (x+1) * interval '30 minute' as timeframe_end
   from generate_series(0,10) x
) x
LEFT JOIN employee t
/* (StartA <= EndB) and (EndA >= StartB) */
ON x.timeframe <= t.timeout
AND x.timeframe_end >= t.timein
GROUP BY x.timeframe
ORDER BY 1

SELECT x.timeframe, count(employee_id)
FROM (
   select time '8:00' + x * interval '30 minute' as timeframe,
          time '8:00' + (x+1) * interval '30 minute' as timeframe_end
   from generate_series(0,12) x
) x
LEFT JOIN employee t
/* (StartA < EndB) and (EndA > StartB) */
ON x.timeframe < t.timeout
AND x.timeframe_end > t.timein
GROUP BY x.timeframe
ORDER BY 1
| timeframe | count |
|-----------|-------|
|  08:00:00 |     0 |
|  08:30:00 |     0 |
|  09:00:00 |     1 |
|  09:30:00 |     1 |
|  10:00:00 |     2 |
|  10:30:00 |     2 |
|  11:00:00 |     3 |
|  11:30:00 |     3 |
|  12:00:00 |     3 |
|  12:30:00 |     1 |
|  13:00:00 |     1 |
|  13:30:00 |     1 |
|  14:00:00 |     0 |

连接条件使用this answer中的公式来检查两个范围是否重叠：

（StartA＆lt; EndB）和（EndA＆gt; StartB）

该演示还显示了查询对边缘情况的行为：

(113, '13:00', '13:01'),
(115, '13:30', '14:00')

后者在13:30开始并在14:00结束，因此它包含在13:30时间范围内，但不包含在14:00时间范围内。 < / p>

|  13:00:00 |     1 |
|  13:30:00 |     1 |
|  14:00:00 |     0 |

问题可能出在雇员在同一时间段内多次开始和完成工作（经常喝咖啡休息的工人），例如：

(113, '13:00', '13:01'),
(113, '13:12', '13:15'),
(113, '13:22', '13:26')

对于此类情况，您需要使用：count(DISTINCT employee_id)

统计不同的员工

Answer 2

尝试这样的事情。

SELECT timeframe,
COUNT (employee_id)
FROM employee a
RIGHT JOIN
(SELECT *
 FROM generate_series (TIMESTAMP '2017-09-01 09:00:00', 
                       TIMESTAMP '2017-09-01 17:00:00', 
               INTERVAL '0.5 HOUR' ) AS timeframe) b 
                 ON b.timeframe >=  timein
                 AND b.timeframe <= timeout
GROUP BY timeframe
ORDER BY timeframe ;

Answer 3

SELECT out_time-in_time time_frame, count(*) FROM
TABLE_NAME GROUP BY out_time-in_time

我针对示例本地数据进行了测试。

employee_id | in_time  | out_time 
-------------+----------+----------
         101 | 09:07:00 | 12:08:00
         102 | 10:07:00 | 17:08:00
         103 | 12:07:00 | 17:08:00
         104 | 12:07:00 | 17:08:00
         105 | 10:07:00 | 17:08:00

查询输出。

time_frame | count 
------------+-------
 07:01:00   |     2
 03:01:00   |     1
 05:01:00   |     2

您可以在找到差异时相应地舍入逻辑。

Answer 4

SQL Fiddle

PostgreSQL 9.6架构设置：

CREATE TABLE emp_time
    ("employee_id" int, "timein" time, "timeout" time)
;

INSERT INTO emp_time
    ("employee_id", "timein", "timeout")
VALUES
    (101, '10:10', '12:59'),
    (102, '9:07', '12:16'),
    (103, '11:16', '12:08')
;

查询1 ：

SELECT 
      slot_start
    , slot_end
    , count(employee_id)
FROM  (
      SELECT slot_start, slot_start + INTERVAL '30 MINUTE' slot_end
      FROM generate_series (TIMESTAMP '2017-01-01 09:00:00', TIMESTAMP '2017-01-01 16:30:00', INTERVAL '30 MINUTE' ) AS slot_start
      ) t 
LEFT JOIN emp_time et ON et.timein < t.slot_end::time and et.timeout > t.slot_start::time
GROUP BY
      slot_start
    , slot_end
ORDER BY
      slot_start
    , slot_end
;

<强> Results ：

|           slot_start |             slot_end | count |
|----------------------|----------------------|-------|
| 2017-01-01T09:00:00Z | 2017-01-01T09:30:00Z |     1 |
| 2017-01-01T09:30:00Z | 2017-01-01T10:00:00Z |     1 |
| 2017-01-01T10:00:00Z | 2017-01-01T10:30:00Z |     2 |
| 2017-01-01T10:30:00Z | 2017-01-01T11:00:00Z |     2 |
| 2017-01-01T11:00:00Z | 2017-01-01T11:30:00Z |     3 |
| 2017-01-01T11:30:00Z | 2017-01-01T12:00:00Z |     3 |
| 2017-01-01T12:00:00Z | 2017-01-01T12:30:00Z |     3 |
| 2017-01-01T12:30:00Z | 2017-01-01T13:00:00Z |     1 |
| 2017-01-01T13:00:00Z | 2017-01-01T13:30:00Z |     0 |
| 2017-01-01T13:30:00Z | 2017-01-01T14:00:00Z |     0 |
| 2017-01-01T14:00:00Z | 2017-01-01T14:30:00Z |     0 |
| 2017-01-01T14:30:00Z | 2017-01-01T15:00:00Z |     0 |
| 2017-01-01T15:00:00Z | 2017-01-01T15:30:00Z |     0 |
| 2017-01-01T15:30:00Z | 2017-01-01T16:00:00Z |     0 |
| 2017-01-01T16:00:00Z | 2017-01-01T16:30:00Z |     0 |
| 2017-01-01T16:30:00Z | 2017-01-01T17:00:00Z |     0 |

SQL：如何按时间帧间隔30分钟选择员工和组的时间范围

4 个答案: