Question

我有一个日期格式和一致价格的行列表（只是一个例子）

date     - price
01/01/14 - $5
01/02/14 - $5
01/03/14 - $1
01/10/14 - $1
01/12/14 - $2

我可以使用以下日期别名

成功地按date进行分组

week(STR_TO_DATE(`date`, '%m/%e/%Y')) AS `date`,

按照MySQL的说法按周分组。

我需要的是按照天的间隔进行分组，这将是从用户界面定义的，即1,2,3,4,5,6天。

我的预期输出是

    SELECT
     `date`,
     SUM`price`,
    FROM `table`
    GROUP BY date range of 3 days

date - price
01/01/14 - 01/03/14 - $11
01/10/14 - 01/12/14 - $3

提议的想法

编辑 - 由于为每个实例创建了一个新列，因此不起作用。见建议＃2

    WEEKOFYEAR(STR_TO_DATE(`ship date`, '%m/%e/%Y')) AS `woy`,
    WEEKDAY(STR_TO_DATE(`ship date`, '%m/%e/%Y')) AS `wday`,

        IF ((SELECT `wday`)='0','range1', '') AS `range`,
        IF ((SELECT `wday`)='1','range1', '') AS `range`,
        IF ((SELECT `wday`)='2','range1', '') AS `range`,
        IF ((SELECT `wday`)='3','range2', '') AS `range`,
        IF ((SELECT `wday`)='4','range2', '') AS `range`,
        IF ((SELECT `wday`)='5','range2', '') AS `range`,
        IF ((SELECT `wday`)='6','range2', '') AS `range`,

提议的想法＃2

    `Ship Date`,
    WEEKOFYEAR(STR_TO_DATE(`ship date`, '%m/%e/%Y')) AS `woy`,
    WEEKDAY(STR_TO_DATE(`ship date`, '%m/%e/%Y')) AS `wday`,

        CASE
            WHEN (SELECT `wday`) = 0 THEN 'range1'
            WHEN (SELECT `wday`) = 1 THEN 'range1'
            WHEN (SELECT `wday`) = 2 THEN 'range1'
            WHEN (SELECT `wday`) = 3 THEN 'range2'
            WHEN (SELECT `wday`) = 4 THEN 'range2'
            WHEN (SELECT `wday`) = 5 THEN 'range3'
            WHEN (SELECT `wday`) = 6 THEN 'range3'
        ELSE 'Other'
            END AS `range`,

Answer 1

创建一个额外的列，定义它应该属于哪个“分组”（参见例如In SQL, how can you "group by" in ranges?），也许根据你需要的逻辑使用case语句（参见例如How does MySQL CASE work?）

SELECT GROUPING, SUM(PRICE) FROM 
    (SELECT
         DATE,
         PRICE,
{CASE statement for grouping logic} GROUPING
        FROM table)
        GROUP BY grouping

如何按天数分组

1 个答案: