Question

我有4个数组，我想将它们组合成1.我可以这样做，但我想从每个数组中取出一个元素，将其推送到我的新数组，然后获取接下来4等等。这就是我得到的：

var a = [ "foo", "bar", "baz", "bam", "bun", "fun" ];
var b = [ 1, 2, 3, 4, 5, 6];
var c=["a","b","c","d","e","f"];
var d=[7,8,9,10,11,12]
var neat=[];
neat= a.concat(b, c,d);
//neat=["foo","bar","baz","bam","bun","fun",1,2,3,4,5,6,"a","b","c","d","e","f",7,8,9,10,11, 12]

我想要的结果是这样的：

//neat=["foo",1,"a",7,"bar",2,"b",8...]

我不确定循环是否有效或是否需要使用其他功能

Answer 1

假设每个源数组的长度相同：

a.forEach((e, i) => {
  neat.push(e, b[i], c[i], d[i]);
};

Answer 2

请尝试以下代码：

＆＃13;

var a = [ "foo", "bar", "baz", "bam", "bun", "fun" ];
var b = [ 1, 2, 3, 4, 5, 6];
var c=["a","b","c","d","e","f"];
var d=[7,8,9,10,11,12]
var neat=[];
//neat= a.concat(b, c,d);
//neat=["foo","bar","baz","b



for (var i = 0; i < a.length ; i++) 
{
neat.push(a[i], b[i], c[i], d[i]);
}
console.log(neat);

＆＃13;

Answer 3

虽然Justins的回答是正确的，但是如果每次阵列的长度不一样，你可以做到

var maxItems = Math.max(a.length,b.length,c.length,d.length);

var neat = [];

for(var i = 0; i < maxItems; i++){

  if(a[i] != undefined){
    neat.push(a[i]);
  }

  if(b[i] != undefined){
    neat.push(b[i]);
  }

  if(c[i] != undefined){
    neat.push(c[i]);
  }

  if(d[i] != undefined){
    neat.push(d[i]);
  }
}

Math.max会在4个数组之间找到最大数量的条目，然后在该数字上找到一个简单的for loop，并在将其推送到{{1之前检查该值是否为undefined }}

请参阅JSFiddle

Answer 4

因为所有数组的长度相等。所以我们可以使用循环轻松完成。

user1   11/11/2018    test

从每个javascript数组concat获取1个元素然后循环到一个数组

4 个答案: