Question

输入：

var array1 = ["12346","12347\n12348","12349"];

步骤：

将\n替换为','并添加到列表中。

输出：

var array2 = ["12346","12347","12348","12349"];

我尝试了以下逻辑，但未达到输出。看起来有些东西不见了。

var array2 = [];

_.forEach(array1, function (item) {               
       var splitData = _.replace(item, /\s+/g, ',').split(',').join();
       array2.push(splitData);
});

输出我的代码：

["12346","12347,12348","12349"]

Answer 1

您可以使用换行符'\n'将其加入，然后按换行符换行。

＆＃13;

var array= ["12346", "12347\n12348", "12349"],
    result = array.join('\n').split('\n');

console.log(result);

＆＃13;

Answer 2

如果你正在使用lodash，那么应用flatmap将是最简单的方法：

＆＃13;

var array1 = ["12346", "12347\n12348", "12349"];
var array2 = _.flatMap(array1, (e) => e.split('\n'));

console.log(array2);
//=> ["12346", "12347", "12348", "12349"]

＆＃13;

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>

＆＃13;

Answer 3

@ Nina答案的替代方法是Array.push.apply使用string.split(/\n/)

var array= ["12346","12347\n12348","12349"];
var result = []

array.forEach(function(item){
   result.push.apply(result, item.split(/\n/))
})

console.log(result);

Concat数组成一个数组（JS或Lodash）

3 个答案: