Question

我有两张地图列表。

 List1=[{1=one,2=two},{1=three,2=two}]
 List2=[{1=one,2=twoss},{1=three,2=twoss}]

我正在尝试比较列表中的地图并以表格形式获取它。虽然我无法获得所需的html格式。所有地图中的键都是相同的，但值可以是不同的，并且尝试在屏幕和数据库之间比较标题和数据库中的键，如果它们匹配，则将用绿色包裹其他红色。所以屏幕上有两排和两排的桌子。头。数据库还有两行和标题。将这些值存储在地图列表中并进行比较。

public String compare(List<Map<String, Object>> list1, List<Map<String, Object>> list2) throws Exception {
    StringBuilder tbe = new StringBuilder();
    String col = "";
    String screen = "";
    String db = "";
    if (list1.size() = list2.size()) {
        for (int i = 0; i < list1.size(); i++) {
            Map<String, Object> a = list1.get(i);
            Map<String, Object> b = list2.get(i);
            for (Map.Entry<String, Object> ent : a.entrySet()) {
                col = col + "<th>" + entry.getKey() + "</th>";
                String k = ent.getKey();
                Object o1 = entry.getValue();
                if (o1.equals(b.get(key))) {
                    screen = screen + "<td bgcolor=green>" + o1 + "</td>";
                    db = db + "<td bgcolor=green>" + b.get(entry.getKey()) + "</td>";
                } else {
                    screen = screen + "<td bgcolor=red>" + o1 + "</td>";
                    db = db + "<td bgcolor=red>" + b.get(entry.getKey()) + "</td>";
                }

            }
            tbe.append("<tr><th>col</th>" + col + "</tr>");
            tbe.append("<tr><th>screen</th>" + screen + "</tr>");
            tbe.append("<tr><th>db</th>" + db + "</tr>");
            tbe.append("</table></html>");
            String tbel = tbe.toString();
            system.out.println(tbel);
            return tbel;
        }
    }
}

我想要的o / p -column header只打印一次，而现在我得到重复的html表。

Answer 1

    public static String compare(List<Map<String, Object>> list1, List<Map<String, Object>> list2) {
        StringBuilder tbe = new StringBuilder();
        String col = "";
        String screen = "";
        String db = "";
        if (list1.size() == list2.size()) {
            for (int i = 0; i < list1.size(); i++) {
                Map<String, Object> a = list1.get(i);
                Map<String, Object> b = list2.get(i);
                for (Map.Entry<String, Object> ent : a.entrySet()) {
                    col = col + "<th>" + ent.getKey() + "</th>";
                    String key = ent.getKey();
                    Object o1 = ent.getValue();
                    if (o1.equals(b.get(key))) {
                        screen = screen + "<td bgcolor=green>" + o1 + "</td>";
                        db = db + "<td bgcolor=green>" + b.get(ent.getKey()) + "</td>";
                    } else {
                        screen = screen + "<td bgcolor=red>" + o1 + "</td>";
                        db = db + "<td bgcolor=red>" + b.get(ent.getKey()) + "</td>";
                    }

                }
                tbe.append("<tr><th>col</th>" + col + "</tr>");
                tbe.append("<tr><th>screen</th>" + screen + "</tr>");
                tbe.append("<tr><th>db</th>" + db + "</tr>");
                tbe.append("</table></html>");
            }
        }
        return tbe.toString();
    }

o / p：

<tr>
    <th>col</th>
    <th>1</th>
    <th>2</th>
</tr>
<tr>
    <th>screen</th>
    <td bgcolor=red>One</td>
    <td bgcolor=red>Two</td>
</tr>
<tr>
    <th>db</th>
    <td bgcolor=red>M2One</td>
    <td bgcolor=red>M2Two</td>
</tr>
</table>

</html>

修复代码中的编译时错误给了我这个输出。这是你期待的吗？

比较java中的映射列表和表中的打印结果

1 个答案: