Question

我正在寻找一个基于桌子的查询，我的商店里有所有商品。该表包含以下列：

location: Shop Name
product: Item Number
attributinstance_id: not in use so it always is NULL
Units:count of Items

我喜欢写一个查询，在那里我可以看到哪些商品在其他商店中，以及它们中的多少和结果应该在同一行。

例如：

       Shop 1   Shop 2  Shop 3
item 1    1        2      5

我可以使用所有树店中可用或可用的物品运行，但是当我查找仅在其中一个树店中可用的物品时，它们将无法显示。有没有人有想法？

到目前为止我的想法：

SELECT Distinct  
products.name AS Artikel,
eins.units AS Europa_Center,
zwei.Units AS O_Strasse,
drei.units AS K_Strasse

FROM stockcurrent eins
LEFT JOIN stockcurrent zwei
ON (eins.product = zwei.product
  AND eins.location ='0'
  AND zwei.location ='a59cb899-27f4-460c-b5df-89a89eaaef75')
LEFT JOIN stockcurrent drei
ON (zwei.product = drei.product 
    AND zwei.location ='a59cb899-27f4-460c-b5df-89a89eaaef75' 
    AND drei.location ='3b53adf5-eaee-4a13-b22b-39d50b14e497')
JOIN products
ON products.id = eins.product
JOIN locations
ON locations.id = eins.location

整体认为是POS系统Unicentas 4.3。表格如下：

Location  Product atributsinstance_id Units 
shop_1    item_1       NULL             5
shop_2    item_1       NULL             1
shop_3    item_1       NULL             0
shop_2    item_2       Null             3  
shop_1    item_3       Null             2
shop_2    item_3       Null             4
shop_3    item_3       Null             1

Answer 1

您需要条件聚合：

 SELECT product_id,
        SUM(CASE WHEN location = 'SHOP1' THEN units ELSE 0 END) as shop_1,
        SUM(CASE WHEN location = 'SHOP2' THEN units ELSE 0 END) as shop_2,
        SUM(CASE WHEN location = 'SHOP3' THEN units ELSE 0 END) as shop_3
 FROM stock
 GROUP BY product_id

查询一个表中的项目

1 个答案: