Question

我在问我的问题之前搜查过：

我有两张桌子。

表信息：

no    | name
1     | david
2     | kang

表 info_kill ：

no   | staffno | skillno
------------------------
1    |    1    |    1
2    |    2    |    1
3    |    2    |    2
4    |    2    |    3

staffno表中的

info_skill和no表中的info是外键。

我想得到：

name包含＆＃39; ka＆＃39;
有skillno 1,2,3。

所以，这是我的sql，

SELECT a.NAME
FROM   (SELECT no,
               NAME
        FROM   info
        WHERE  NAME LIKE '%ka%') AS a
       INNER JOIN info_skill AS b
               ON a.no = b.staffno
       INNER JOIN info_skill AS c
               ON a.no = c.staffno
       INNER JOIN info_skill AS d
               ON a.no = d.staffno
WHERE  b.skillno = '1'
       AND c.skillno = '2'
       AND d.skillno = '3'

我想知道的是这部分。

       INNER JOIN info_skill AS b
               ON a.no = b.staffno
       INNER JOIN info_skill AS c
               ON a.no = c.staffno
       INNER JOIN info_skill AS d
               ON a.no = d.staffno
WHERE  b.skillno = '1'
       AND c.skillno = '2'
       AND d.skillno = '3'

还有其他办法吗？

Answer 1

试试这个：

SELECT I.name
FROM info I
    JOIN info_skill S
         ON I.no = S.staffno
WHERE I.name LIKE'%ka%" AND
      S.skillno=1 OR
      S.skillno=2 OR
      S.skillno=3

这意味着：

您加入外键后的两个表
然后使用LIKE %ka%

ka

现在，您需要检查skillno是否等于1,2或3

如果这不是您所需要的，那么请通过解释您正在寻找的内容来更清楚地说明您的问题。

Answer 2

select a.name 
from info a
inner join info_skill as b on a.no = b.staffno
where b.skillno in (1,2,3)
and name like '%ka%'
group by a.name
having count(distinct b.skillno) = 3

关于选择查询，一个表多个结果

2 个答案:

SQLFiddle demo