我有两张桌子,一张用于销售,另一张用于库存。 我想从销售表中选择位置ID,商品ID,尺寸ID和销售数量,而我只想从库存表中选择库存数量来获取销售表中相同的位置ID和尺寸ID,如下所示:
销售表:
------------------------------------
| loc_id | item_id | size_id | qty |
------------------------------------
| 5 | 11321 | 1 | 3 |
| 5 | 11321 | 2 | 7 |
| 5 | 11321 | 3 | 9 |
股票表:
------------------------------------------------------
| loc_id | item_id | size_id | sales_qty | stock_qty |
------------------------------------------------------
| 5 | 11321 | 1 | 5 | 3 |
| 5 | 11321 | 2 | 9 | 7 |
| 5 | 11321 | 3 | 4 | 9 |
所以select之后的结果应该是这样的:
SELECT SUM(T1.qty) AS `salesQty`, SUM(T2.qty) AS `stockQty`, T1.size_id,
T1.loc_id
FROM sales T1
INNER JOIN stock T2 ON T2.item_id = T1.item_id AND T2.size_id = T1.size_id
WHERE T1.item_id = '11321'
AND T1.size_id IN (1,2,3)
AND T1.loc_id IN (5)
GROUP BY T1.size_id, T1.loc_id
这是我尝试做的事情:
<body>
html code here
<script type="text/javascript">
(function () {
some javascript code here
})();
</script>
<button type="button">Delete javascript</button>
</body>
但库存数量总是错误的!
答案 0 :(得分:0)
select
q1.loc_id
,q1.item_id
,q1.size_id
,sum(case when q1.Type='Sales' then q1.Qty else 0 end) as sales_qty
,sum(case when q1.Type='Stock' then q1.Qty else 0 end) as stock_qty
from (
select
T1.loc_id
,T1.item_id
,T1.size_id
,'Sales' as Type
,SUM(T1.qty) AS Qty
from sales T1
group by
T1.loc_id
,T1.item_id
,T1.size_id
union all
select
T2.loc_id
,T2.item_id
,T2.size_id
,'Stock' as Type
,SUM(T2.qty) AS Qty
from stock T2
group by
T2.loc_id
,T2.item_id
,T2.size_id) q1
group by
q1.loc_id
,q1.item_id
,q1.size_id