我目前正在为vector<double>
实现滑动窗口功能。问题是我似乎不能cout
价值观?当我输出它时,我似乎得到了记忆位置,而不是实际值..
我需要处理窗口所包含的数据,因此对值的访问将是整洁的。
typedef double SAMPLE;
std::vector<std::vector<SAMPLES> > loaded_files;
//Some init
std::vector<SAMPLE>::iterator it;
for (it = loaded_file.samples[0].begin() ; (it + (NUM_SECONDS*SAMPLE_RATE)) != loaded_file.samples[0].end(); ++it)
{
auto window = *it;
std::cout << "printing the window!" << std::endl;
std::cout << &(window) << std::endl; // prints out memory location?
}
答案 0 :(得分:1)
每次打印窗口内容时,都需要遍历窗口本身。这可以通过更改const tables = document.querySelectorAll('.wikitable');
const table = tables[1];
const tr = table.querySelectorAll('tbody tr');
var output = [];
for(var i = 0; i < tr.length; i++){
const theTD = Array.from(tr[i].querySelectorAll('td'));
const theText = theTD.map(item => item.innerText);
if(theText.length > 0 ){
output.push(theText);
}
}
循环的内容来完成,如下所示:
for
请注意,窗口的宽度为typedef double SAMPLE;
std::vector<<SAMPLES>> loaded_files;
//Some init
std::vector<SAMPLE>::iterator it;
for (it = loaded_file.samples[0].begin(); (it + (NUM_SECONDS*SAMPLE_RATE)) != loaded_file.samples[0].end(); ++it)
{
std::cout << "printing the window!" << std::endl;
std::vector<SAMPLE>::iterator wit; // window iterator
for (wit = it; wit != it + (NUM_SECONDS*SAMPLE_RATE); ++wit)
{
std::cout << *wit << ',';
}
std::cout << std::endl;
}
。这可以存储在(NUM_SECONDS*SAMPLE_RATE)
或类似的变量中,以帮助提高可读性。