Question

我的这个表包含用户电子邮件和公司ID。用户可以在其帐户中添加多个公司。因此，用户可以在其电子邮件中拥有多个公司ID。我想写一个查询来计算用户（我已经编写过这个查询），并将它们标识为多个公司用户。因此，在我的COUNT语句中，我应该如何写，如果该电子邮件中有多个公司ID标识为多公司用户。

以下是我为了获取具有多个Id的电子邮件列表而编写的查询。

SELECT email, COUNT(company_id) AS count_of_companies 
FROM database
GROUP BY email
HAVING COUNT(company_id) > 1
ORDER BY count_of_companies DEC;

谢谢

Answer 1

假设您需要识别并将用户列表作为多公司获取，我已修改您的查询

 SELECT EmailID, CASE  WHEN count_of_companies >  1  THEN 'MultiCompany User' ELSE 'Single' END FROM
   (
         SELECT EmailID, COUNT(companyID) AS count_of_companies 
          FROM #temp_company
          GROUP BY EmailID
   )t

Answer 2

通过电子邮件统计公司和分区：

select email,
 (case when count(companyid)over(partition by email) > 1
  then 'multi-company-user'
else 'single-company-user'
end) as count_of_companies
from your_table

Answer 3

试试这个

SELECT EMAIL
        ,CASE 
            WHEN COUNT(COMPANY_ID) > 1
                THEN 'MULTI-COMPANY'
            ELSE 'SINGLE-COMPANY'
            END AS COUNT_OF_COMPANIES
        FROM DATABASEA 
        GROUP BY EMAIL
        ORDER BY COUNT_OF_COMPANIES DESC

在SQL中如何编写CASE和COUNT

3 个答案: