这是我从图库中获取数据的代码,并将其保存在SQLite数据库中,但它无法正常工作
.....
case PICK_FROM_GALLERY:
Bundle extras2 = data.getExtras();
if (extras2 != null) {
Bitmap yourImage = extras2.getParcelable("data");
// convert bitmap to byte
ByteArrayOutputStream stream = new ByteArrayOutputStream();
yourImage.compress(Bitmap.CompressFormat.PNG, 100, stream);
byte imageInByte[] = stream.toByteArray();
Log.e("output before conversion", imageInByte.toString());
// Inserting Contacts
Log.d("Insert: ", "Inserting ..");
db.addContact(new Contact(resultCode, "Android", imageInByte));
Intent i = new Intent(Editor.this, Editor.class);
startActivity(i);
finish();
}
break;
}
}
答案 0 :(得分:0)
存储图像的Uri,通过Uri,您可以在ImageView中设置图像
Uri imageUri;
Intent pickUpImage = new Intent(Intent.ACTION_PICK);
pickUpImage.setType("image/*");
startActivityForResult(pickUpImage, 1);
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == 1 && resultCode == Activity.RESULT_OK) {
Uri uri = data.getData();
imageUri = uri;
profilePic.setImageURI(imageUri);
}
}