Question

我尝试从Gallery中获取图像并将其保存到SQLite数据库。所以我将在我的应用程序的其他部分使用此图像。我从Gallery获取图像并在imageView中显示它工作正常，但当我尝试将其保存在数据库应用程序崩溃时。我使用以下代码转换NSData中的图像，然后将其保存到数据库字段，类型为BLOB。

NSData * imageData;

-(void)imagePickerController:(UIImagePickerController *)picker didFinishPickingImage:(UIImage *)img editingInfo:(NSDictionary *)editInfo {
    [picker dismissModalViewControllerAnimated:YES];

    ImageView.image= img;

    imageData= UIImagePNGRepresentation(_ImageView.image);
}

和我的SQLite插入方法是：

-(void) CreateGoal:(NSString *)Title :(NSString *) Description :(NSString *)NextStep :(NSString *) Date :(NSData *)image{

    //Get list of directories in Document path
    NSArray * dirPath = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);

    //Define new path for database
    NSString * documentPath = [[dirPath objectAtIndex:0] stringByAppendingPathComponent:@"GoalBook.db"];


    if(!(sqlite3_open([documentPath UTF8String], &db) == SQLITE_OK))
    {
        NSLog(@"An error has occured.");
        return;
    }else{
        NSString *insertSQL = [NSString stringWithFormat:
                               @"INSERT INTO createGoal(title, description, nextstep, date, image) VALUES ('%@','%@','%@', '%@', '%@')",
                               Title, Description, NextStep, Date, image];

        const char *sql = [insertSQL UTF8String];

        sqlite3_stmt *sqlStatement;
        if(sqlite3_prepare_v2(db, sql, -1, &sqlStatement, NULL) != SQLITE_OK)
        {
            NSLog(@"Problem with prepare statement");
            return;
        }else{

            if(sqlite3_step(sqlStatement)==SQLITE_DONE){
                sqlite3_finalize(sqlStatement);
                sqlite3_close(db);
            }
        }

    }

}

我使用这种方法来保存我的数据：

[self.database CreateGoal:_Goaltitle.text :_goaldescription.text :_goalnext.text :getGoaldate :imageData];

我用Google搜索了很多答案，但经过多次试验后我放弃了。

任何人都可以说明这有什么问题吗？

提前致谢

在iOS中的SQlite数据库中保存图像，该数据库从Gallery中获取

0 个答案: