Question

我的DataFrame由numpy数组组成：

                                                col1  \
0  [[[0.878617777607, 0.712102459231, 0.652479557...   
1  [[[0.0815294305642, 0.793893471424, 0.24718091...   
2  [[[0.611498467162, 0.880551635123, 0.949764900...   

                                                col2  \
0  [[[0.390629506277, 0.0318899771374, 0.28308523...   
1  [[[0.578710371447, 0.385239304185, 0.330119601...   
2  [[[0.843661601339, 0.402833961663, 0.535083132...   

                                                col3  
0  [[[0.162446865578, 0.165619948624, 0.622459063...  
1  [[[0.859362904741, 0.415994003318, 0.706308170...  
2  [[[0.0559589731135, 0.307840549475, 0.80023067...

如何计算此DataFrame中的平均numpy数组？结果应该是一个numpy数组，表示我的DataFrame中所有numpy数组的平均值。

代码

import numpy as np
import pandas as pd

df = pd.DataFrame({'col1': [np.random.rand(4,4,4) for i in range(3)],
                   'col2': [np.random.rand(4,4,4) for i in range(3)],
                   'col3': [np.random.rand(4,4,4) for i in range(3)]})

预期输出（对于上面的代码）：一个numpy数组，表示所有numpy数组的平均值

array([[[ 0.44091592,  0.81509111,  0.94968265,  0.60255149],
        [ 0.49263418,  0.69519008,  0.05023616,  0.67871942],
        [ 0.72771491,  0.9593636 ,  0.84673578,  0.43407915],
        [ 0.5884133 ,  0.63940507,  0.53364733,  0.51271129]],

       [[ 0.55612852,  0.58847166,  0.37781843,  0.7693527 ],
        [ 0.40610198,  0.05897461,  0.945253  ,  0.66332715],
        [ 0.74352406,  0.34969614,  0.50384616,  0.90582012],
        [ 0.38734233,  0.85533348,  0.94869219,  0.2863428 ]],

       [[ 0.81782769,  0.8856158 ,  0.68744406,  0.76579709],
        [ 0.05843924,  0.83090709,  0.99446694,  0.74937771],
        [ 0.11898717,  0.38715644,  0.50348724,  0.41903257],
        [ 0.21359555,  0.93407981,  0.20531033,  0.71017461]],

       [[ 0.88758803,  0.40433699,  0.02888434,  0.91075114],
        [ 0.84047283,  0.87119432,  0.14844659,  0.87643422],
        [ 0.06412383,  0.60458874,  0.47277274,  0.12969607],
        [ 0.31917517,  0.15647266,  0.89773897,  0.77962999]]])

我尝试了df.mean()，但它返回了Series([], dtype: float64)

还尝试df.mean(axis=1).mean()并返回NaN

更新

一个更简单的例子

df = pd.DataFrame({'col1': [np.array([[1,3],[4,2]]), np.array([[1,1],[3,2]])],
                   'col2': [np.array([[1,3],[3,3]]), np.array([[2,3],[3,1]])]})

数据帧

Out[31]: 
               col1              col2
0  [[1, 3], [4, 2]]  [[1, 3], [3, 3]]
1  [[1, 1], [3, 2]]  [[2, 3], [3, 1]]

预期产出：

In[42]: (df.iloc[0,0]+df.iloc[0,1]+df.iloc[1,0]+df.iloc[1,1])/4.

Out[42]: 
array([[ 1.25,  2.5 ],
       [ 3.25,  2.  ]])

Answer 1

抱歉，我之前误解了你的问题，请试试。

df = pd.DataFrame({'col1': [np.array([[1.,3.],[4.,2.]]), np.array([[1.,1.],[3.,2.]])],
                   'col2': [np.array([[1.,3.],[3.,3.]]), np.array([[2.,3.],[3.,1.]])]})

print df
print np.expand_dims(df.as_matrix(), axis=1).mean()

Answer 2

我不知道为什么熊猫会对在DataFrame上计算mean()过敏，但这是一种解决方法：

>>> df = pd.DataFrame({'col1': [np.array([[1,3],[4,2]]), np.array([[1,1],[3,2]])],
...                    'col2': [np.array([[1,3],[3,3]]), np.array([[2,3],[3,1]])]})
>>> np.mean([df[col].mean() for col in df.columns], axis=0)
array([[1.25, 2.5 ],
       [3.25, 2.  ]])

执行df.mean(axis=0).mean(axis=1)会引发异常：

ValueError: If using all scalar values, you must pass an index

计算pandas DataFrame中的平均numpy数组

2 个答案: