如何在sequelize中获得多对多关系中间表的数据

Question

我在sequelize orm中有一个问题。 通过中间表，表之间存在多对多的关系。

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CREATE OR REPLACE TRIGGER  trigger_credit_bf_update
BEFORE UPDATE ON credit_card 
FOR EACH ROW
BEGIN
INSERT INTO credit_card_log_history (cc_type, action) Values 
(:old.cc_type, 'Before_Update_Credit_Card');
END;

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当我通过Id找到图像时，我通过include得到了所有标签，但我无法在tagImages表中获得值列。

这是我的查询声明：

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 const Tag = sequelize.define('tag', {
    name: Sequelize.STRING,
    type: Sequelize.CHAR
  })
  const Image = sequelize.define('image', {
    thumb: Sequelize.STRING,
    original: Sequelize.STRING,
    status: Sequelize.INTEGER,
    width: Sequelize.INTEGER,
    height:   Sequelize.INTEGER,
    fileSize:  Sequelize.STRING,
  })

const TagImages = sequelize.define('TagImages', {
    value: Sequelize.STRING,
})

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并且我的console.log中没有值列。我应该怎么做到？

Answer 1

Sequelize应在每个TagImage上添加Tag属性。