Question

我是Spring MVC的新手。我尝试创建小型hello world应用程序，但它没有按预期运行。我总是收到错误 org.springframework.web.servlet.DispatcherServlet noHandlerFound 警告：在DispatcherServlet中找不到带有URI [/FitnessTracker/greeting.html]的HTTP请求的映射，其名称为＆＃39; fitTrackerServlet＆＃39;

我知道这个错误很常见，谷歌上有很多链接，但没有一个适合我。任何帮助将不胜感激。

以下是代码段

HelloController.java

@Controller
public class HelloController {

@RequestMapping(value = "/greeting")    
public String sayHello(Model model) {
model.addAttribute("greeting","Hello World!!!!");
return "hello";
}}

的hello.jsp

<%@ page language="java" contentType="text/html; charset=UTF-8"
    pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>
Insert title here
</title>
</head>
<body>
<h1>
${greeting}
</h1>
</body>
</html>

fitTrackerServlet-servlet.xml中

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:p="http://www.springframework.org/schema/p"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/mvc 
                    http://www.springframework.org/schema/mvc/spring-mvc-3.2.xsd
                    http://www.springframework.org/schema/beans 
                    http://www.springframework.org/schema/beans/spring-beans.xsd
                    http://www.springframework.org/schema/context
                        http://www.springframework.org/schema/context/spring-context.xsd">

<mvc:annotation-driven/>
<context:annotation-config/>
<context:component-scan base-package="com.firstspringmvc.controller"/>
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver" 
        p:prefix="/WEB-INF/jsp/" 
        p:suffix=".jsp"/>
</beans>

的web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee" 
    xmlns:web="http://java.sun.com/xml/ns/javaee"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    version="3.0">
    <display-name>Archetype Created Web Application</display-name>
    <servlet>
    <servlet-name>fitTrackerServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>fitTrackerServlet</servlet-name>
        <url-pattern>*.html</url-pattern>
    </servlet-mapping>  
</web-app>

项目结构

Answer 1

URL /greeting最后没有.html，因此servlet不会使用DispatcherServlet，因为*.html模式与/ greeting不匹配，这个将导致404。

更改您的web.xml：

<servlet-mapping>
    <servlet-name>fitTrackerServlet</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

org.springframework.web.servlet.DispatcherServlet noHandlerFound：Spring MVC

1 个答案: