Question

我正在尝试用汇编语言制作Tic Tac Toe如何切换播放器？这是我的代码。

.686 
.MODEL flat, stdcall
.STACK
INCLUDE Irvine32.inc

.data
tic BYTE "TIC TAC TOE GAME"
player BYTE "PLAYER 1 (X) : PLAYER 2 (O)"
myarray1 BYTE '1' , ' ' , '|' , ' ' , '2' , ' ' , '|' ,' ' ,'3'
myarray2 BYTE '4' , ' ' , '|' , ' ' , '5' , ' ' , '|' ,' ' ,'6'
myarray3 BYTE '7',  ' ' , '|' , ' ' , '8' , ' ' , '|' ,' ' ,'9'
choise BYTE 'X','O'
player1 BYTE "Player 1 select your position ",0
player2 BYTE "Player 2 select your position ",0
info byte ?
turn BYTE 2

.code 
main PROC
mov bl,1
mov ecx,9
L13:
push ecx        
call BOARD
call GAME
pop ecx
call clrscr         
loop L13

BOARD proc


;TO DISPLAY TIC TAC TOE GAME
mov ecx, LENGTHOF tic
mov esi,Offset tic
L0:
mov al,[esi]
call writechar
inc esi
loop l0
call crlf
call crlf


;TO DISPLAY PLAYER INFO
mov ecx,LENGTHOF player
mov esi,OFFSET player
l6:
mov al,[esi]
call writechar
inc esi
loop L6
call crlf
call crlf


;LOOP TO DISPLAY FIRST ARRAY
mov ecx,LENGTHOF myarray1
mov esi,OFFSET myarray1
L1:
mov al,[esi]
call writechar
inc esi
loop L1
call crlf

;LOOP TO DISPLAY SECOND ARRAY
mov ecx,LENGTHOF myarray2
mov esi,OFFSET myarray2
L2:
mov al,[esi]
call writechar
inc esi
loop L2
call crlf

;LOOP TO DISPLAY THIRD ARRAY
mov ecx,LENGTHOF myarray3
mov esi,OFFSET myarray3
L3:
mov al,[esi]
call writechar
inc esi
loop L3
call crlf
call crlf 

ret
BOARD endp

GAME proc
mov ecx,LENGTHOF player1
mov esi,OFFSET player1
L4:
mov al,[esi]
call writechar
inc esi
loop L4
call crlf


call readint
mov info,al

cmp al,1
je one

cmp al,2
je two

cmp al,3
je three

cmp al,4
je four

cmp al,5
je five

cmp al,6
je six

cmp al,7
je seven

cmp al,8
je eight

cmp al,9
je nine

one:
mov al,choise
xchg al,[myarray1]
ret

two:
mov al,choise
xchg al,[myarray1+4]
ret

three:
mov al,choise
xchg al,[myarray1+8]
ret

four:
mov al,choise
xchg al,[myarray2]
ret

five:
mov al,choise
xchg al,[myarray2+4]
ret

six:
mov al,choise
xchg al,[myarray2+8]
ret

seven:
mov al,choise
xchg al,[myarray3]
ret

eight:
mov al,choise
xchg al,[myarray3+4]
ret

nine:
mov al,choise
xchg al,[myarray3+8]
ret


GAME endp

exit
main endp
end main

Answer 1

.code 
main PROC
mov bl,1
mov ecx,9
L13:
push ecx        
call BOARD
call GAME
pop ecx
call clrscr         
loop L13

主要代码中已经提供了解决播放器切换问题的提示！请注意mov bl, 1指令，目前在您的程序中完全没有必要。您可以使用BX寄存器来表示当前播放器。最简单的是玩家1的BX=0和玩家2的BX=1。

在 main 循环的每次迭代中，您必须使用BX轻松切换xor bx, 1中的值。

    xor     bx, bx   ;Sets BX=0, so player 1 starts
    mov     ecx, 9
L13:
    push    ecx
    call    BOARD
    call    GAME
    pop     ecx
    call    clrscr
    xor     bx, 1    ;This switches players, 0 becomes 1 and 1 becomes 0
    loop    L13

在 GAME 程序中，您需要

显示个性化提示。您不再需要 Player2 消息。

GAME proc
    mov     ecx, LENGTHOF player1
    mov     esi, OFFSET player1
    lea     ax, ["1" + bx]
    mov     [esi + 7], al     ;Modifies message to show "1" or "2"
L4:
    mov     al, [esi]
    call    writechar
    inc     esi
    loop    L4
    call    crlf

在9个不同场合选择正确的角色（＆＃34; X＆＃34;对于玩家1或＆＃34; O＆＃34;对于玩家2）。
您撰写mov al, choise的任何地方，现在都需要mov al, [choise + bx]。

汇编语言中的Tic Tac Toe游戏

1 个答案: