所以我试图编写一种方法来重播一个tic tac toe游戏后,有人获胜,失败或关系。 所以基本上我试图重播工作,不起作用。如果玩家1获胜并且我输入1进行重播,则会询问玩家2他们的输入。
伪代码轮廓:
do {
set entire 2d array to '*'
do {
player 1 input
does game tie?
does player 1 win
player 2 input
does game tie?
does player 2 win
} while no one wins
} while replay = 1
我的实际代码:
//tie check, replay, use pointer notation
#include <iostream>
using namespace std;
void initialize(char [][3]);
void player1(char [][3]);
void player2(char [][3]);
void display(char [][3]);
char check(char [3][3]);
int checkWin(int);
int tie(int);
int askReplay();
int main()
{
char board[3][3];
char end = '*';
int row1, column1, row2,column2;
int replay = 0;
int turns = 0;
//replay loop
do {
//set board to *
initialize(board);
display(board);
do {
//player 1 turn
player1(board);
turns++;
display(board);
//if turns = 9 then tie
replay = tie(turns);
//check if player 1 won
end = check(board);
replay = checkWin(end);
//player 2 turn
player2(board);
turns++;
display(board);
//if turns = 9 then tie
replay = tie(turns);
//check if player 2 won
end = check(board);
replay = checkWin(end);
} while (end == '*');
} while (replay == 1);
return 0;
}
void initialize(char (*array)[3])
{
for (int i = 0;i < 3;i++)
for (int j = 0;j < 3;j++)
array[i][j] = '*';
cout << "New Game\n";
}
void player1(char (*array)[3])
{
int row1, column1;
cout << "Player 1\nRow: ";
cin >> row1;
while (row1 < 0 || row1 > 2) {
cout << "Enter a number between 0 and 2 for Row:: ";
cin >> row1;
}
cout << "Column: ";
cin >> column1;
while (column1 < 0 || column1 > 2) {
cout << "Enter a number between 0 and 2 for Column: ";
cin >> column1;
}
if (array[row1][column1] == '*')
array[row1][column1] = 'X';
else {
cout << "Space Occupied\n";
player1(array);
}
}
void player2(char (*array)[3])
{
int row2,column2;
cout << "Player 2\nRow: ";
cin >> row2;
while (row2 < 0 || row2 > 2) {
cout << "Enter a number between 0 and 2 for Row: ";
cin >> row2;
}
cout << "Column: ";
cin >> column2;
while (column2 < 0 || column2 > 2) {
cout << "Enter a number between 0 and 2 for Column: ";
cin >> column2;
}
if (array[row2][column2] == '*')
array[row2][column2] = 'O';
else {
cout << "Space Occupied\n";
player2(array);
}
}
void display(char (*array)[3])
{
for (int x = 0;x < 3;x++) {
for (int y = 0;y < 3;y++)
cout << *(*(array + x) + y) << " ";
cout << endl;
}
}
char check(char (*array)[3])
{
int i;
/* check rows */
for(i = 0; i < 3; i++)
if(array[i][0] == array[i][1] && array[i][0] == array[i][2])
return array[i][0];
/* check columns */
for(i = 0; i < 3; i++)
if(array[0][i] == array[1][i] && array[0][i] == array[2][i])
return array[0][i];
/* test diagonals */
if(array[0][0] == array[1][1] && array[1][1] == array[2][2])
return array[0][0];
if(array[0][2] == array[1][1] && array[1][1] == array[2][0])
return array[0][2];
return '*';
}
int checkWin(int over)
{
if (over == '*')
return 0;
if (over == 'X')
cout << "Player 1 Won!\n";
else if (over == 'O')
cout << "Player 2 Won!\n";
//ask if they want to play again
int answer;
answer = askReplay();
switch (answer) {
case 1:
return 1;
case 2:
cout << "Thank you for playing.\n";
exit(0);
}
}
int tie(int count)
{
if (count == 9) {
int answer;
cout << "Tie game";
answer = askReplay();
switch (answer) {
case 1:
return 1;
case 2:
cout << "Thank you for playing.\n";
exit(0);
}
}
}
int askReplay()
{
int input;
do {
cout << "Play Again?\n1.Yes\n2.No\nEnter 1 or 2: ";
cin >> input;
if (input > 2 || input < 1)
cout << "Invalid Option\n";
} while(input > 2 || input < 1);
return input;
}
答案 0 :(得分:2)
听起来你的主循环遇到了麻烦。
我建议制作一个控制哪个播放器正在运行的变量,然后切换它。
do
{
set entire 2d array to '*'
current player = 0
do
{
(current player + 1) input
does game tie?
does (current player + 1) win
current player = (current player + 1) % 2
}while no one wins
}while replay = 1
看看是否能让你更进一步。
答案 1 :(得分:0)
您可能想要查找Memento设计模式。