我制作了一款名为“Nim＆＃39;游戏”的游戏。在Netbeans。基本上，产生15-30之间的随机数量的宝石，并且计算机和玩家轮流采取1-3个宝石，直到没有留下。拿最后一块石头的玩家输了。我以jframe形式对此进行编码。我想确保玩家不输入大于3，小于1且大于总石头数的数字，所以我做了一个带有if语句的while循环，用于符合要求的输入和else语句如果他们没有遇到。我的问题是，当玩家确实输入了不应输入的数字时，不会显示任何错误消息，游戏将继续正常进行。 这是我认为问题所在：
public int playerInput(){
// Getting the user input and converting it into an integer
int userIn = Integer.parseInt(txtIn.getText());
//
boolean input = false;
// Do this while the input isn't between 1-3 and higher than the total amount of rocks
while(!input){
//
if (userIn < 3 || userIn > 1 || userIn < totalStone){
//
input = true;
}
//
else{
// Output an error message
txtaOut.setText(txtaOut.getText() +"\nEnter a number between 1 - 3 and less than the amount of stones left.");
}
}
// return the amount of rocks the user takes
return userIn;
}
以下是游戏的大部分代码（我将使用随机斜杠进行评论）：
public void computerMove() {
// Generating a number for the computer's move
int comIn = (int)(Math.random() * 2) + 1;
// If number generated is bigger than the total stones,
if (comIn > totalStone){
// Get the difference between the total and the random number
int totalComDiff = Math.abs(totalStone - comIn);
// Subtract the difference from the random number
comIn -= totalComDiff;
// Substract the rocks taken from the total
totalStone -= comIn;
// Display a message of the rocks taken and the rocks left
txtaOut.setText(txtaOut.getText() +"\nThe computer picked up " +comIn +" stone(s). There are " +totalStone +" stones left.");
}
// Otherwise, if the random number is smaller than the total,
else if (comIn < totalStone){
// Substract the rocks taken from the total
totalStone -= comIn;
// Display a message of the rocks taken and the rocks left
txtaOut.setText(txtaOut.getText() +"\nThe computer picked up " +comIn +" stone(s). There are " +totalStone +" stones left.");
}
// If the total equals amount the computer takes,
else if (totalStone == comIn){
// Substract the rocks taken from the total
totalStone -= comIn;
// Display a message of the rocks taken and the rocks left
txtaOut.setText(txtaOut.getText() +"\nThe computer picked up " +comIn +" stone(s). There are " +totalStone +" stones left.");
// Display a message that says the player wins
txtaOut.setText(txtaOut.getText() +"\nThere are no more stones left. The player wins!");
}
// Otherwise, if the amount of stones is 0,
else if (totalStone == 0){
// Display an end game message
txtaOut.setText(txtaOut.getText() + "\nThe game has ended.");
}
}
public void playerMove(){
// If there are no more stones left,
if (playerInput() == totalStone){
// Subtracting how much the player took from the total amount of rocks
totalStone -= playerInput();
// Displaying how many rocks were taken and how many are left
txtaOut.setText(txtaOut.getText() +"\nYou picked up " +playerInput() +" stone(s). There are " +totalStone +" stones left.");
// Display a message that says the computer wins
txtaOut.setText(txtaOut.getText() + "\nThere are no more stones left. The computer wins.");
}
//
else if (playerInput() != totalStone){
// Subtracting how much the player took from the total amount of rocks
totalStone -= playerInput();
// Displaying how many rocks were taken and how many are left
txtaOut.setText(txtaOut.getText() +"\nYou picked up " +playerInput() +" stone(s). There are " +totalStone +" stones left.");
}
//
else if (totalStone <= 0){
//
txtaOut.setText(txtaOut.getText() + "\nThe game has ended.");
}
}
private void btnEnterActionPerformed(java.awt.event.ActionEvent evt) {
//
if (totalStone > 0){
// Display how many rocks there are
txtaOut.setText(txtaOut.getText() +"\nThere are " +totalStone +" stones.");
// The player does their move
playerMove();
}
//
if (totalStone > 0){
// Computer does a turn
computerMove();
}
//
else if (totalStone == 0){
//
txtaOut.setText(txtaOut.getText() + "\nThe game has ended.");
}
}
private void btnResetActionPerformed(java.awt.event.ActionEvent evt) {
// Generating another random number
totalStone = (int)(Math.random() * 15) + 15;
// Clearing all the textfields
txtIn.setText("");
txtaOut.setText("");
// Outputting the number of starting stones
txtaOut.setText(txtaOut.getText() +"There are " +totalStone +" stones. It's your turn.");
}
答案 0 :(得分：0)
你需要看起来像这样：
2012
a : 2
b : 2
2013
a : 1
b : 0
而且，它会起作用。
最好首先检查条件是否无效，然后如果验证通过则执行else块中的正常流程。
你编写它的方式，因为||，if条件总是正确的代表'或'所以你要求天气userIn小于3或大于1或小于totalStone总是如此。
另一方面＆amp;＆amp;代表'和'和'！'代表不。因此，您基本上希望满足所有条件，并检查它们是否不是通过将它们放入括号并放置！ （否定）在前面
如果不满足条件，您还需要再次提示用户。否则它将永远运行并冻结ui。
答案 1 :(得分：0)
如果用户输入的号码不正确，则应提示他们输入新号码。在你的代码中，它将永远停留在循环中。
您还应该使用＆amp;＆amp;来检查是否满足所有条件。 您需要一个（＆lt; = 3）AND（＆gt; = 1）AND（＆lt; = totalStones）
的数字public int playerInput () {
int userIn;
do {
System.out.println("Enter a number between 1 - 3 and less than the amount of stones left.")
userIn = Integer.parseInt (txtIn.getText ());
} while (!(userIn <= 3 && userIn >= 1 && userIn <= totalStone));
在不满足条件的情况下，这将继续循环。