Question

#Asks player for their name and whether they wish to enter or not
character_name = input(" Welcome to The Tenabris Manor, what is your 
name?:")
print("")
print(" The towering gates stand before you to the large Manor, do you 
enter?")
print("")
inp = ""
while inp != "enter" and inp != "leave":
inp = input(" enter enter or leave: ")
if inp != "enter" and inp != "leave":
    print(" You must type enter or leave")

if inp == "enter":
print(" You push with all your might on the large gates, it swings open with 
a loud clunk.")
if inp == "leave":
print("")
print(" You turn around and go back, probably for the best.")
print("")
print(" Your character", character_name, "turned back and never returned.")
input(" Press enter to exit")
SystemExit("")

def choose_room():
#key = False is so the person does not have the key until going upstairs
global key
key = False
while True: 
    print("")
    print(" Bookshelfs line the walls, a staircase is to the left and a door 
is straight ahead.")
    print("")
    print(" Type 'a' to: Go up the stairs")
    print(" Type 'b' to: To go through the door")
    print(" Type 'c' to: To check the bookshelfs")
    ans = input("")
    if ans=='a':
        print(" You walk up the creaking stairs")
        print(" At the top of the spiral staircase is a small observatory.")
        print(" Looking around on some of stacks of books littering the room  
you")
        print(" find a small key!")
        key = True
        continue
    elif ans=='b':
#The door detects whether the key is True or not/they have the key or not.
         if key == True:
             print(" You open the door with the small key.")
         elif key == False:
             print(" The door is locked, you will need a key to go through 
it.")
             continue
             return
             choose_room()
         else:
             print("The door is locked, you will need a key to go through 
it.")
             continue
             return
             choose_room()

    else:
        ans == 'c'
        print(" You look through the thousands of books.")
        print(" None of them interest you.")
        continue
        return
    choose_room()

请原谅我可怕的编码，这是我的第一个项目，我很惊讶它首先起作用。

这也是我关于堆栈溢出的第一篇文章。

我的问题是这段代码完美地完成了我需要的所有内容，但是当我去添加更多细节时，我决定稍后这样做并删除我“添加”的所有内容现在代码无法运行除了select select_room（）之前的第一部分：

当我运行它时没有出现错误信息，只是第一部分然后忽略了“def choose_room（）：”的位。

嗯，我能想到的就是添加它可能有助于找到原因。下次我在更改任何内容之前复制文件，这样就不会再发生了。

如果没有人能找到问题所在，我会尝试从头开始重新制作程序。

Answer 1

在Python中，缩进是语法的一部分，因此如果你有不正确的缩进信息，你的代码就不会像你期望的那样运行。

更正缩进：

#Asks player for their name and whether they wish to enter or not
character_name = input(" Welcome to The Tenabris Manor, what is your name?:")
print("")
print(" The towering gates stand before you to the large Manor, do you enter?")
print("")
inp = ""
while inp != "enter" and inp != "leave":
    inp = input(" enter enter or leave: ")
    if inp != "enter" and inp != "leave":
        print(" You must type enter or leave")

    if inp == "enter":
        print(" You push with all your might on the large gates, it swings open with a loud clunk.")
    if inp == "leave":
        print("")
        print(" You turn around and go back, probably for the best.")
        print("")
        print(" Your character", character_name, "turned back and never returned.")
        input(" Press enter to exit")
        SystemExit("")

def choose_room():
    #key = False is so the person does not have the key until going upstairs
    global key
    key = False
    while True: 
        print("")
        print(" Bookshelfs line the walls, a staircase is to the left and a door is straight ahead.")
        print("")
        print(" Type 'a' to: Go up the stairs")
        print(" Type 'b' to: To go through the door")
        print(" Type 'c' to: To check the bookshelfs")
        ans = input("")
        if ans=='a':
            print(" You walk up the creaking stairs")
            print(" At the top of the spiral staircase is a small observatory.")
            print(" Looking around on some of stacks of books littering the room you")
            print(" find a small key!")
            key = True
            continue
        elif ans=='b':
             #The door detects whether the key is True or not/they have the key or not.
             if key == True:
                 print(" You open the door with the small key.")
             elif key == False:
                 print(" The door is locked, you will need a key to go through it.")
                 continue
                 return
                 choose_room()
             else:
                 print("The door is locked, you will need a key to go through it.")
                 continue
                 return
                 choose_room()

        else:
            ans == 'c'
            print(" You look through the thousands of books.")
            print(" None of them interest you.")
            continue
            return
choose_room()

Answer 2

您定义了函数choose_room()但从未使用/调用它。它会像这样。

#...
if inp == "enter":
    print(" You push with all your might on the large gates, it swings open with a loud clunk.")
    choose_room()
#...

确保在调用之前定义该函数。将def choose_room():...置于脚本顶部或实际choose_room

之前

在我的Text Adventure中，Python不会打印任何超过我的def的内容

2 个答案: