Question

如果您不理解我的标题，请忽略它，然后阅读本文.... 所以这是我的代码...

   alphabets=["a", "b","c", "d","e","f"]
   nums=["one","two"] 

   for num in nums[:2]: 
       print(num.title()) 
       print(alphabets[:3])

输出就像这样......

    one
    ['a','b','c']
    two
    ['d','e','f']

我不知道该怎么做我已经尝试了很多不同的东西。我只需要将所有代码分成八行，我希望得到类似的输出......

    one
    ['a','b','c']
    two
    ['a','b','c']

唯一的问题是第二行输出相同的东西＆＃34; a，b和c＆＃34;相反，我想要＆＃34; d，e和f＆＃34;。请帮忙！提前谢谢！

Answer 1

一个非常简单的解决方案，也许是unpythonic：

alphabets=["a", "b","c", "d","e","f"]
nums=["one","two"]

i = 0
for num in nums[:2]:
    print(num.title())
    print(alphabets[i:i+3])
    i = i + 3

Answer 2

为尽可能通用，您可以使用字典：

alphabets=["a", "b","c", "d","e","f"]
nums=["one","two"] 
converter = {"one":1, "two":2, "three":3, "four":4} #can be expanded upon
new_alpha = {a:b for a, b in zip(nums, [alphabets[i:i+len(nums)+1] for i in range(0, len(alphabets), len(nums)+1)])}
for a, b in sorted(new_alpha.items(), key=lambda x:converter[x[0]]):
    print(a)
    print(b)

输出：

one
['a', 'b', 'c']
two
['d', 'e', 'f']

如何在python中打印单词下的单词？

2 个答案: