Question

def no_underscored_words(words_string):
    '''Receives a string (word_string containing zero or 
    more comma separated words. Returns  a list of words
    in words_string that do not contain any underscore 
    character in them.'''
    result = []
    word_list = words_string.split(",")
    for word in word_list:
        if word != "_":
            result.append(word)
    return result

这就是我得到的，但失败了:(

任何建议都将不胜感激

问题要求

print（no_underscored_words（'12，_init __，main'））并期望结果应为['12'，'main']

打印（no_underscored_words（'my_list，your_list'））并期望结果应为[]

Answer 1

替换

if word != "_":

与

if "_" not in word:

Answer 2

让我们定义函数no_under。为方便起见，我们在ipython：

中以交互方式对其进行定义

In [7]:: def no_under(word_string):
  ...:     return [word for word in word_string.split(',') if not '_' in word]
  ...:

两个测试用例表明这可以按预期工作：

In [8]: no_under('12,_init__,main')
Out[8]: ['12', 'main']

In [9]: no_under('my_list,your_list')
Out[9]: []

如何运作

该函数包含单个命令：

return [word for word in word_string.split(',') if not '_' in word]

word_string.split(',')将逗号分隔的word_string转换为单词列表。如果if子句为True，则这些单词包含在最终列表中。 '_' in word测试该单词是否包含下划线。如果它没有，它将包含在我们返回的最终列表中。

Answer 3

def no_underscored_words(words_string):
    '''Receives a string (word_string containing zero or 
    more comma separated words. Returns  a list of words
    in words_string that do not contain any underscore 
    character in them.'''
    result = []
    word_list = words_string.split(",")
    for word in word_list:
        if not('_' in word):
            result.append(word)
    return result

print(no_underscored_words('12,_init__,main'))
print(no_underscored_words('my_list,your_list'))

输出：

['12', 'main']
[]

如何打印没有下划线的单词

3 个答案:

如何运作