首先,感谢您抽出宝贵时间阅读本文
问题:
示例
SELECT Article.ID, Article.Name, Article.Price, EV.EV, Pic.Upload_Datum
FROM Article
LEFT JOIN Pic ON Articel.ID = Pic.Artikle_ID
LEFT JOIN Stock ON Stock.ID = Article.Lager_ID
LEFT JOIN EV ON EV.ID = Article.EV_ID
WHERE Article.Activ = "1"
AND Stock.trader_ID = "2"
AND Article.stock_ID = "1"
AND pic.Uploaddate IS NOT BETWEEN 1510903702 AND 1503127702
LIMIT 10
示例resutl
ID上传
2624919 1489736525
2624919 1489736528
2624920 1507295386
2624920 1507295389
2624920 1507295397
这是我得到的结果之一,但我只需要这两个:
2624919 1489736525
2624920 1507295386
现在我得到foreach Article.ID不止一条记录,因为在" pic"表中有任何一篇文章的图片。问题是,我只需要sql找到的第一张图片。
我希望以正确的方式提问。
问候 B3rgi
答案 0 :(得分:1)
如果您真的不关心要为您的照片拍摄哪些数据,请参阅下面的示例,它将拍摄您文章的第一张照片。
SELECT Article.ID, Article.Name, Article.Price, EV.EV,
SELECT Pic.Upload_Datum
FROM Pic
WHERE Articel.ID = Pic.Artikle_ID
LIMIT 1) AS Upload_Datum
FROM Article
LEFT JOIN Stock ON Stock.ID = Article.Lager_ID
LEFT JOIN EV ON EV.ID = Article.EV_ID
WHERE Article.Activ = "1"
AND Stock.trader_ID = "2"
AND Article.stock_ID = "1"
LIMIT 10