Question

早安全部所以我被要求在每周的基础上看看订购的地方如此简单。

DECLARE @vYearWeek INT
SET @vYearWeek = '201745';

SELECT
  LEFT(Orders.ProductWhsLocation,1) AS 'Area',
  COUNT(Orders.HostOrderNo) AS 'Picked'
FROM CHDS_Common.dbo.OMOrder Orders
  LEFT JOIN CHDS_Management.dbo.Calendar Cal ON CONVERT(date, Orders.EarliestPickDate) = Cal.DT 
  WHERE Orders.PicksetNo <> 0 AND cal.YWK = @vYearWeek
  GROUP BY LEFT(ProductWhsLocation,1)
  ORDER BY LEFT(ProductWhsLocation,1);

这很好用......我现在需要更深入地把它洒进几天。现在逻辑会说这很简单：

DECLARE @vYearWeek INT
SET @vYearWeek = '201745';

SELECT
  LEFT(Orders.ProductWhsLocation,1) AS 'Area',
  CASE WHEN Cal.DW = 1 THEN COUNT(Orders.HostOrderNo) ELSE 0 END AS 'Sunday',
  CASE WHEN Cal.DW = 2 THEN COUNT(Orders.HostOrderNo) ELSE 0 END AS 'Monday',
  CASE WHEN Cal.DW = 3 THEN COUNT(Orders.HostOrderNo) ELSE 0 END AS 'Tuesday',
  CASE WHEN Cal.DW = 4 THEN COUNT(Orders.HostOrderNo) ELSE 0 END AS 'Wednesday',
  CASE WHEN Cal.DW = 5 THEN COUNT(Orders.HostOrderNo) ELSE 0 END AS 'Thuresday',
  CASE WHEN Cal.DW = 6 THEN COUNT(Orders.HostOrderNo) ELSE 0 END AS 'Friday',
  CASE WHEN Cal.DW = 7 THEN COUNT(Orders.HostOrderNo) ELSE 0 END AS 'Saturday'
FROM CHDS_Common.dbo.OMOrder Orders
  LEFT JOIN CHDS_Management.dbo.Calendar Cal ON CONVERT(date, Orders.EarliestPickDate) = Cal.DT 
WHERE Orders.PicksetNo <> 0 AND cal.YWK = @vYearWeek
GROUP BY LEFT(ProductWhsLocation,1)
ORDER BY LEFT(ProductWhsLocation,1);

但是你们都知道错误:( 列'CHDS_Management.dbo.Calendar.DW'在选择列表中无效，因为它不包含在聚合函数或GROUP BY子句中。

任何有关排序的帮助都会非常感谢所有人。

Answer 1

Pivot Query可以在这种情况下使用

- 改进答案

步骤1：在日历表或日期编号中按日期获取星期几

第2步：使用数据透视表按天获取行数

SELECT *

FROM
(
    SELECT
  LEFT(Orders.ProductWhsLocation,1) AS 'Area',
  COUNT(Orders.HostOrderNo) OrderCount,
  DATENAME(weekday,cal.dt) 'DayName'
  FROM CHDS_Common.dbo.OMOrder Orders
  LEFT JOIN CHDS_Management.dbo.Calendar Cal ON CONVERT(date, Orders.EarliestPickDate) = Cal.DT 
WHERE Orders.PicksetNo <> 0 AND cal.YWK = @vYearWeek
GROUP BY LEFT(ProductWhsLocation,1),cal.dw
) AS SourceTable PIVOT(SUM(OrderCount) FOR [DayName] IN([SUNDAY]
                                                        ,[MONDAY]
                                                        ,[TUESDAY]
                                                        ,[WEDNESDAY]
                                                        ,[THURSDAY]
                                                        ,[FRIDAY]
                                                        ,[SATURDAY] )

) AS PivotTable;

将一周的数据分成几周的SQL日期

1 个答案: