Question

我试图获得本周的以下输出 -

Full Name    | Mon           | Tue  | Wed           | Thu  | Fri  | Sat  | Sun
Peter Smith  | 09:00 - 12:00 | NULL | 08:30 - 13:00 | NULL | NULL | NULL | 10:00 - 12:13
Peter Smith  | 13:00 - 17:00 | NULL | 14:30 - 16:00 | NULL | NULL | NULL | 13:00 - 17:14
Paul Stevens | 09:00 - 12:00 | NULL | 08:30 - 13:00 | NULL | NULL | NULL | 10:00 - 12:13

这是在日志中显示时钟，从表中拉出 -

**ClockInLogs**
ID - INT
UserID - INT
ClockDateTimeIn - DateTime
ClockDateTimeOut - DateTime
Status - INT (ClockedIn/ClockedOut)

来源数据 -

ID | UserID | ClockDateTimeIn         | ClockDateTimeOut        | Status
1  | 10000  | 2013-07-30 13:40:39.913 | 2013-07-30 13:42:20.113 | 0
2  | 10000  | 2013-07-30 14:13:10.947 | 2013-07-30 14:25:15.570 | 0
3  | 10001  | 2013-07-30 14:13:52.817 | 2013-07-30 14:25:19.063 | 0

从名为Users的联接表中提取全名。

我是如何获得所需输出的？我知道我需要做一个PIVOT但是无法弄清楚如何在细胞内显示时间。

谢谢！

Answer 1

declare @test table (ID int, UserID int, ClockDateTimeIn datetime, ClockDateTimeOut datetime, [Status] bit)
declare @user table (ID int, Name nvarchar(128))

insert into @test
select 1, 10000, '2013-07-30 13:40:39.913', '2013-07-30 13:42:20.113', 0 union all
select 2, 10000, '2013-07-30 14:13:10.947', '2013-07-30 14:25:15.570', 0 union all
select 3, 10001, '2013-07-30 14:13:52.817', '2013-07-30 14:25:19.063', 0 union all
select 3, 10001, '2013-07-29 10:13:52.817', '2013-07-30 18:25:19.063', 0

insert into @user
select 10000, 'Martin Smith' union all
select 10001, 'Paul Stevens'

;with CTE as 
(
    select
        u.Name,
        left(datename(weekday, t.ClockDateTimeIn), 3) as Col,
        convert(nvarchar(5), t.ClockDateTimeIn, 108) + ' - ' + convert(nvarchar(5), t.ClockDateTimeOut, 108) as Value,
        row_number() over (partition by u.Name, datename(weekday, t.ClockDateTimeIn) order by t.ClockDateTimeIn) as ID
    from @test as t
        left outer join @user as u on u.ID = t.UserID
)
select P.*
from CTE as C
pivot 
(
    min(Value) for Col in ([Mon], [Tue], [Wen], [Thu], [Fri], [Sat], [Sun])
) as P
order by Name, ID

SQL FIDDLE EXAMPLE

SQL PIVOT一周中的几天

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