Question

我得到这样的错误：元组类型的值'（键：字符串，值：AnyObject）'没有成员'下标'

我尝试在线搜索，但我不明白，它总是说有关将其更改为字典数组的内容但是当我将数据解析为[[String：AnyObject]]时，它会给我一个错误。

这是我的上下文代码

`//
//  MapViewViewController.swift
//  On the Map!
//
//  Created by Belal Elsiesy on 11/13/17.
//  Copyright © 2017 Elsiesy Industries. All rights reserved.
//

import UIKit

import MapKit

class MapViewViewController: UIViewController, MKMapViewDelegate {

    @IBOutlet weak var MapView: MKMapView!

    override func viewDidLoad() {
        super.viewDidLoad()

        // Do any additional setup after loading the view.
        getLocations()
        let appDelegate = UIApplication.shared.delegate as! AppDelegate

        let locations  = appDelegate.locationData
        var annotations = [MKPointAnnotation]()

        // When the array is complete, we add the annotations to the map.

        for location  in locations! {

            // Notice that the float values are being used to create CLLocationDegree values.
            // This is a version of the Double type.
            let lat = CLLocationDegrees(location["latitude"] as! Double)
            let long = CLLocationDegrees(location["longitude"] as! Double)

            // The lat and long are used to create a CLLocationCoordinates2D instance.
            let coordinate = CLLocationCoordinate2D(latitude: lat, longitude: long)

            let first = location["firstName"] as! String
            let last = location["lastName"] as! String
            let mediaURL = location["mediaURL"] as! String

            // Here we create the annotation and set its coordiate, title, and subtitle properties
            let annotation = MKPointAnnotation()
            annotation.coordinate = coordinate
            annotation.title = "\(first) \(last)"
            annotation.subtitle = mediaURL

            // Finally we place the annotation in an array of annotations.
            annotations.append(annotation)
        }
        // When the array is complete, we add the annotations to the map.
        self.MapView.addAnnotations(annotations)
    }
}




    /*
    // MARK: - Navigation

    // In a storyboard-based application, you will often want to do a little preparation before navigation
    override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
        // Get the new view controller using segue.destinationViewController.
        // Pass the selected object to the new view controller.
    }
    */
func getLocations() {

        var request = URLRequest(url: URL(string: "https://parse.udacity.com/parse/classes/StudentLocation")!)
        request.addValue("QrX47CA9cyuGewLdsL7o5Eb8iug6Em8ye0dnAbIr", forHTTPHeaderField: "X-Parse-Application-Id")
        request.addValue("QuWThTdiRmTux3YaDseUSEpUKo7aBYM737yKd4gY", forHTTPHeaderField: "X-Parse-REST-API-Key")
        let session = URLSession.shared
        let task = session.dataTask(with: request) { data, response, error in
            if error != nil { // Handle error...
                ////////////////////////DO THIS LATER
            }
            print(String(data: data!, encoding: .utf8)!)
        let parsedResult: [String:AnyObject]!
            do {
                parsedResult = try JSONSerialization.jsonObject(with: data!, options: .allowFragments) as!  [String : AnyObject]


                let appDelegate = UIApplication.shared.delegate as! AppDelegate
                appDelegate.locationData = parsedResult
            } catch {
                print("Could not parse the data as JSON: '\(data)'")

            }


        }
        task.resume()
    }


`

Answer 1

从Apple文档：您可以使用for-in循环遍历字典中的键值对。字典中的每个项都作为（键，值）元组返回，并且您可以将元组的成员分解为临时常量或变量，作为迭代的一部分：

for (key, value) in dictionary {
    print(key)
    print(value)
}

并注意您的代码的另一个问题： 1）函数getLocation（）中存在异步代码，并且在viewDidLoad（）中分配

let locations  = appDelegate.locationData

位置等于零。

2）Swift 4具有解析JSON的有用功能，研究它。现在你得到只有一个键值对的字典，键等于“result”

Answer 2

在尝试对元组数组进行排序时，我遇到了此错误。原因是元组成员没有像数组那样被引用。

对于元组，您使用location.latitude

（对于数组，您将使用location["latitude"]）

用常规花括号声明数组，而不用数组的方括号声明

let location = (latitude: 2.3, longitude: 1.2)

let c = location.latitude   // c is now 2.3

我知道这个问题很旧，但是我希望这可以帮助其他搜索没有成员“下标”的人

元组类型'（键：字符串，值：AnyObject）的值没有成员'下标'

2 个答案: