Question

在此之前我在目标C工作。现在我需要用快速语言编写我的项目代码。在使用AFNetworking类进行Web服务调用时，我创建了一个名为FSAPI的类，我在其中创建了2个块

typedef void (^requestCompletionBlock) (AFHTTPRequestOperation *operation, id responseObject);
typedef void (^requestFailureBlock) (AFHTTPRequestOperation *operation, NSError *error);

以及以下登录方法

//****************** Login Service **********************//
- (void)loginUserWithUsername:(NSString *)username
             andPassword:(NSString *)password
             andGrant_type:(NSString *)grantType
     withCompletionBlock:(requestCompletionBlock)completionBlock
         andFailureBlock:(requestFailureBlock)failureBlock;

现在我不知道如何才能打电话。我已经创建了桥接头文件并导入了FSAPI.h。

    FSAPI.sharedClient().loginUserWithUsername("", andPassword: "", andGrant_type: "", withCompletionBlock: requestCompletionBlock() {
     AFHTTPRequestOperation, id in

        //to do

        }, andFailureBlock: requestFailureBlock () {

        })

+ (id)sharedClient {
    static FSAPI *sharedClient = nil;
    static dispatch_once_t oncePredicate;
    dispatch_once(&oncePredicate, ^{
        sharedClient = [[self alloc] initWithBaseURL:[NSURL     URLWithString:baseServerURL]];
    });
    return sharedClient;
}

请有人帮助我。提前谢谢。

Answer 1

试试这个

将id替换为instancetype。

+ (instancetype)sharedClient {
    static FSAPI *sharedClient = nil;
    static dispatch_once_t oncePredicate;
    dispatch_once(&oncePredicate, ^{
        sharedClient = [[self alloc] initWithBaseURL:[NSURL     URLWithString:baseServerURL]];
    });
    return sharedClient;
}

Answer 2

试试这个，因为swift中的块被视为闭包，

FSAPI.sharedClient().loginUserWithUsername("", andPassword: "", andGrant_type: "", withCompletionBlock: { (operation, response) -> Void in {

    //to do in success case 

    }, andFailureBlock: { (operation, error) -> Void in {

        //to do in error case 

        })

类型的价值＆＃39; AnyObject＆＃39;没有会员＆＃39; loginUserWithUsername＆＃39;

2 个答案: