Question

如何拆分一组数字并将正数推送到数组而将负数推送到另一个？ var myarr = [1,2,3，-1,5，-3];

Answer 1

您可以将singn推送到对象的相应属性，其中值是数组。

＆＃13;

var array = [1, 2, 3, -1, 5, -3],
    positive = [],
    negative = [],
    hash = { 1: positive, '-1': negative };
    
array.forEach(a => hash[Math.sign(a)].push(a));

console.log(positive);
console.log(negative);

＆＃13;

将零视为正数：

＆＃13;

var array = [1, 2, 3, -1, 5, -3, 0],
    positive = [],
    negative = [],
    hash = { true: positive, false: negative };
    
array.forEach(a => hash[a >= 0].push(a));

console.log(positive);
console.log(negative);

＆＃13;

过滤的经典方式

＆＃13;

var array = [1, 2, 3, -1, 5, -3, 0],
    negative = [],
    positive = array.filter(a => a >= 0 || (negative.push(a), false));

console.log(positive);
console.log(negative);

＆＃13;

Answer 2

试试这个：

var myarr = [ 1,2,3,-1.5,-3 ];

var positive = [];
var negative = [];

for( key in myarr ) {

    var item = myarr[ key ];

    if( item < 0 ) {

        negative.push( item );

    }
    else {

        positive.push( item );

    }

}

Answer 3

检查每个数组值是否小于0，如果小于0则检查不是否为负数，否则为正

试试这段代码

＆＃13;

var myarr = [1, 2, 3, -1, 5, -3];
var pos = [];
var neg = [];
for (i = 0; i < myarr.length; i++) {
  if (myarr[i] < 0) {
    neg.push(myarr[i]);
  } else {
    pos.push(myarr[i]);
  }
}

console.log(neg);
console.log(pos);

＆＃13;

你如何拆分一组数字并将正数推送到数组而将负数推送到另一个？

3 个答案: