Question

def main():
i = int( input ("Enter an interger, the input ends if it is 0: "))
count_pos = 0
count_neg = 0
total = 0
if (i != 0):
    while (i != 0):
        if (i > 0):
            count_pos += 1
        elif (i < 0):
            count_neg += 1
        total += i
    i = int( input ("Enter an interger, the input ends if it is 0: "))
    count = count_pos + count_neg

print ("The number of positives is", count_pos)
print ("The number of negatives is", count_neg)
print ("The total is", total)

文件＆＃34;＆＃34;，第16行打印（＆＃34;肯定数是＆＃34;，count_pos） ^ IndentationError：unindent与任何外部缩进级别都不匹配

Answer 1

请参阅我们的列表，例如sample_list

sample_list = [1, 5, -9, 6, 7, -7, -2, -4, 2, 3]

或者

sample_list = []
while True:
    a = int(raw_input())
    if a==0: break
    else:sample_list.append(a)

现在，要获得列表的长度

sample_list_length = len(sample_list)

其中len（）是一个内置函数，它返回任何可迭代对象的长度，如字符串，列表等。

positive_number = 0
negative_number = 0
for dummy_number in sample_list:
    if dummy_number>=0:
        positive_number+=1
    else:
        negative_number+=1

print "There are",positive_number,"positive numbers"
print "There are",negative_number,"negative numbers"
print "There are",sample_list_length,"total numbers"

Answer 2

您的代码存在一些问题。

首先，

while (i != 0):
    if (i > 0):
        count_pos += 1
    elif (i < 0):
        count_neg += 1
    total += i

是一个无限循环。 i永远不会更改，因此如果第一次i!=0为True，则它始终为True。

接下来，

i = int( raw_input ("Enter an interger, the input ends if it is 0: "))
count = count_pos + count_neg

完全没必要。以下代码中均未使用i而非count。

固定代码：

def main():
    count_pos = 0
    count_neg = 0
    while True:
        i = int( input ("Enter an interger, the input ends if it is 0: "))
        if i > 0:
            count_pos += 1
        elif i < 0:
            count_neg += 1
        else:
            break

    print ("The number of positives is", count_pos)
    print ("The number of negatives is", count_neg)
    print ("The total is", count_pos+count_neg)

正数和负数

2 个答案: