Question

假设我有一个具有以下结构的示例数据框

cars=c("A","A","A","A", "B","B","B","B", "C","C","C","C","A","A","A","A", "B","B","B","B", "C","C","C","C")
vendor=c("d","e","f","g", "d","e","f","g", "d","e","f","g", "d","e","f","g", "d","e","f","g", "d","e","f","g")
state=c(1,1,1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2,2,2)
PS_mean=c(100, 110, 120, 130, 90, 95, 140, 180, 70, 80, 120, 150, 100, 110, 120, 130, 90, 95, 140, 180, 70, 80, 120, 150)
PS_stdv=c(10, 20, 30, 40, 10, 20, 30, 40, 10, 20, 30, 40, 10, 20, 30, 40, 10, 20, 30, 40, 10, 20, 30, 40)
mycars=data.frame(cars, vendor, state, PS_mean, PS_stdv)

我现在想要使用像

这样的dcast进行重塑

mycars_cov<-dcast(setDT(mycars[c('cars','state','PS_mean','PS_stdv')]), cars~state, value.var=c("PS_mean", "PS_stdv"), car_PS_var("PS_mean", "PS_stdv"))

如您所见，函数“car_PS_var”是用户定义的，带有两个输入

car_PS_var<- function(x,y){
   x<-as.numeric(x)
   y<-as.numeric(y)
   z=sd(x)*sd(y)/mean(x)
   return(z)
}

我不知道如何应用一个将两个“value.var”作为参数的函数，并返回一个。通常使用dcast，您只能将函数应用于一个变量，这就是为什么 car_PS_var("PS_mean", "PS_stdv") 不起作用

在这种形式下，R会抛出一些错误，因为它不能在dcast函数中输入两个输入。

那我怎么能正确地做到这一点？如果你建议任何其他R方法完成任务，也没关系

Answer 1

不确定我是否理解了你的目标，但从我的解释来看，一个快速而又肮脏的方法是先按车分组并先说明，然后创建新列，然后dcast新数据表

mycars <- as.data.table(mycars)

temp <- mycars[, .(z = car_PS_var(PS_mean, PS_stdv)),
              by = c("cars", "state")]

dcast(temp, cars ~ state)

   cars        1        2
1:    A 1.449275 1.449275
2:    B 4.325825 4.325825
3:    C 4.545340 4.545340

dcast函数从两个值变量中获取参数

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