Question

我需要显示一个图表，其中可以显示游戏，得分，所有时间排名，每周排名，与朋友排名。

我有两张桌子：
1）high_scores（playerid，gameid，得分，时间（时间戳））
2）朋友（playerid，friendid）

我想知道如何使用最少数量的查询来实现这一目标。

我正在使用PHP＆amp; MySQL用于我的游戏网站。

Answer 1

可以设法查询它，如下所示：

SELECT
    gamescores.gameid,
    COUNT(*)+1 AS rank,
    playergamescores.total,
    gamename,
    foldername
FROM (
    SELECT gameid, playerid, SUM( score ) AS total, time
    FROM high_scores
    GROUP BY gameid, playerid
    ORDER BY gameid, total DESC
) AS gamescores
INNER JOIN
(
    SELECT gameid, SUM(score) AS total
    FROM high_scores
    WHERE playerid = 361822
    GROUP BY gameid
    ORDER BY total DESC
) AS playergamescores
ON playergamescores.gameid = gamescores.gameid
INNER JOIN gamemaster
ON gamescores.gameid = gamemaster.gameid
WHERE gamescores.total > (
    SELECT SUM( score ) AS total
    FROM high_scores
    WHERE gamescores.gameid = gameid
    AND playerid = 361822                       
)
GROUP BY gamescores.gameid
ORDER BY gamescores.time DESC

感谢您的回答...... -Navi

Answer 2

计算一次数据，而不是每次请求。

你有2个解决方案：

cron / async job
在每次插入/更新/删除/截断

根据比赛计算球员排名

2 个答案: