如何将args按升序排序?

时间:2017-10-30 15:50:59

标签: java arrays string sorting

我正在尝试排序' args'按升序排列,我错过了什么? 每当我在命令行中放置随机参数时前两个都可以工作,我得到一个数组和一个字符串。但是,在第三个我希望数组按升序排序。输入始终为0.

我也尝试创建自己的算法但是它还没有尝试过。工作

import java.util.Arrays;

public class tri {

public static void main (String[] args) 
{
    if (args.length < 3) {
        System.out.println("Re-execute with at least 3 arguments");
        System.exit(-1);
    }

    System.out.println("\n Printing as an array:");

    for (int i=0; i < args.length; i++)     //print each word 
        System.out.println(args[i]);

    String str = "";

    for (int i=0; i < args.length; i++) 
        str = str + args[i] + " ";          //concatenate into a string

    System.out.println("\n Printing as a string:");

    System.out.println(str);                //print the string


    System.out.println("\n Printing after sorting:");


     int [] sorted = new int[args.length];
     Arrays.sort(sorted);                   //sort the sorted array
     System.out.println(Arrays.toString(sorted));

    /*for (int i=0; i < args.length - 1; i++)  {
        System.out.print(args[i] + " ");  
    }*/
}
}

输出:

Printing as an array:
ball
cat
ship

Printing as a string;
ball cat ship

Printing after sorting;
[0, 0, 0]

1 个答案:

答案 0 :(得分:1)

我很确定这是你正在尝试做的事情:

import java.util.Arrays;

public class Tri {
    public static void main(String[] args) {
        Arrays.sort(args);
        System.out.println(Arrays.toString(args));
    }
}

作为程序参数,我输入"abc" "efg" "abz",输出为

[abc, abz, efg]

Process finished with exit code 0