我想生成一个由100个数字组成的数组,并求出它们的平均值和总和。我能够做到这一点,但是我无法使数字的输出升序。我是Java的新手。
import java.util.Random;
public class randomNumberGen
{
public static void main(String [] args)
{
Random r=new Random();
double sum = 0; // is double so to prevent int division later on
int amount = 100;
int upperBound = 100;
for (int i = 0; i < amount; i++){
int next = r.nextInt(upperBound) + 1; // creates a random int in [1,100]
System.out.println(next);
sum += next; // accumulate sum of all random numbers
}
System.out.println("Your average is: " + (sum / amount));
System.out.println("Your sum is: " + (sum));
}
}
答案 0 :(得分:1)
这很容易。但是我没有在您的代码中看到任何数组。我为您创建了示例代码。您可以寻求更多帮助。
public static void main(String[] args) {
SecureRandom random = new SecureRandom(); // it is better to use this library
double sum = 0; // is double so to prevent int division later on
int amount = 100;
int upperBound = 100;
int[] array = new int[amount]; // create an array with amount size
for (int i = 0; i < amount; i++) {
array[i] = random.nextInt(upperBound) + 1; // creates a random int in [1 , upperBound]
sum += array[i]; // accumulate sum of all random numbers
}
Arrays.sort(array); // sort array in default order which is ascending
System.out.println(Arrays.toString(array)); // toString is a way to print all of array, without iterate it and print it
System.out.println("Your average is: " + (sum / amount));
System.out.println("Your sum is: " + sum);
}
答案 1 :(得分:0)
有很多不同的排序方法。对于初学者,请从Bubble Sort或Insertion Sort开始。插入排序稍好一些,因为平均而言运行速度稍快一些。
答案 2 :(得分:0)
我提供使用一种特殊的集合在内部对数字进行排序,而无需使用一种排序算法(例如我们PriorityQueue
):
public static void main(String[] args) {
final int amount = 100;
Random random = new SecureRandom();
Queue<Integer> queue = new PriorityQueue<>(amount, Comparator.naturalOrder()); // Comparator.reverseOrder() for reverse order
int sum = 0;
for (int i = 0; i < amount; i++) {
int val = random.nextInt(100) + 1;
sum += val;
queue.add(val);
}
System.out.println(Arrays.toString(queue.toArray()));
System.out.println("Your average is: " + (double)sum / amount);
System.out.println("Your sum is: " + sum);
}