提交表单两次显示空白输入错误

Question

我使用php，Ajax和amp;为我的网站制作了一个表单jQuery的。当我第一次提交带有一些输入的表单时它工作正常，但第二次没有重新加载页面它显示错误。使用类id和类型attr时，html输入标签很简单。

我想要的是如果用户提交表单，代码也会第二次运行。

php和jquery：

 if(isset($_POST['submit'])){
        $name = $_POST['name'];
        $website = $_POST['website'];
      //  $category = $_POST['category'];
        $toscheckbox = $_POST['toscheckbox'];

        $errorEmpty = false;
        $website_error = false;
        $name_error = false;
        $toscheckbox_error = false;

        if(empty($name) || empty($website) || empty($toscheckbox)){
            echo "<span class='alert alert-danger' role='alert'>Please fill in all fields!</span>";
            $errorEmpty = true;
        }
        elseif (!filter_var($website, FILTER_VALIDATE_URL)){
            echo "<span class='alert alert-danger' role='alert'>Write a valid URL!</span>";
            $website_error = true;
        }
        elseif (!preg_match("/^[a-zA-Z0-9][a-zA-Z0-9 \t]*$/", $name)) {
          echo "<span class='alert alert-danger' role='alert'>Please check your Website Name</span>";
          $name_error = true; 
        }
        else {
            echo "<span class='alert alert-success'>Thanks your submission listed in our Database!</span>";
        }
    }
    else {
        echo "<span class='alert alert-danger'>There was something wrong with your form</span>";
    }

    <script>
       // $("#name, #website, #toscheckbox").removeClass("border border-danger");

        var errorEmpty = "<?php echo $errorEmpty; ?>";
        var website_error = "<?php echo $website_error; ?>";
        var name_error = "<?php echo $name_error; ?>";
        var toscheckbox_error = "<?php echo $toscheckbox_error; ?>";

        if(errorEmpty == true){
            $("#name, #website, #toscheckbox").addClass("border border-danger");  
        }
        if(website_error == true) {
            $("#website").addClass("border border-danger");
        }
        if(name_error == true) {
            $("#name").addClass("border border-danger");
        }
        if (errorEmpty == false && name_error == false && website_error == false && toscheckbox_error == false) {
           $("#name, #website, #toscheckbox").val("");
       }
    </script>

<script>
  $(document).ready(function() {
    $("form").submit(function(event){
      event.preventDefault();
      var name  = $("#name").val();
      var website  = $("#website").val();
      var toscheckbox  = $("#toscheckbox").val();
      var submit  = $("#submit").val();
      $(".text-danger").load("ajaxreturn.php", {
        name: name,
        website: website,
        toscheckbox: toscheckbox,
        submit: submit
      });
    });
  });
</script>

编辑HTML：

<input class="form-control" id="name" type="text" name="name">
<input name="toscheckbox" class="form-check-input" id="toscheckbox" type="checkbox" value="ToS">
<input class="form-control form-control" id="website" type="text" name="website">