Question

编辑：将PHP更改为推荐代码，仍然无法在页面上显示成功/错误。

我正在尝试让这个联系页面正常工作，但是当我点击提交按钮时似乎正在破坏。单击后，它会将我重定向到/contact_form.php并显示空白页面。如果所有表单都已正确填写，则会发送消息。如果其中任何一个错误或未填写，则会显示相同的空白页。

HTML：

<form method="post" action="contact_form.php">
    <div class="input-group-lg">
        <label for="name">Your Name<i>*</i></label>
        <input name="name" type="text" class="form-control" placeholder="What should I call you?">
    </div>
    <div class="input-group-lg">
        <label for="email">Email Address<i>*</i></label>
        <input name="email" type="email" class="form-control" placeholder="Email Address">
    </div>
    <div class="input-group-lg">
        <label for="phone">Phone Number</label>
        <input name="phone" type="text" class="form-control" placeholder="Phone Number">
    </div>
    <div class="input-group-lg">
        <label for="message">Message<i>*</i></label>
        <textarea name="message" class="form-control" placeholder="What's on your mind?"></textarea>
    </div>
    <div class="input-group-lg">
        <label for="human">What is 2 + 2? (Anti-spam)<i>*</i></label>
        <input name="human" type="text" class="form-control" placeholder="2 + 2 = ?">
    </div>
    <div class="text-center">
        <?php echo $result; ?>    
    </div>
    <div class="text-center">
        <input name="submit" type="submit" value="Send Message" class="btn btn-custom"></input>
    </div>
</form>

PHP：

<?php
if ($_POST["submit"]) {
    $name = $_POST['name'];
    $email = $_POST['email'];
    $phone = $_POST['phone'];
    $message = $_POST['message'];
    $human = intval($_POST['human']);
    $from = 'From: example';
    $to = 'example@gmail.com';
    $subject = 'Message from X';

    $body ="From: $name\n E-Mail: $email\n Phone: $phone\n Message:\n $message";
    // Check if name has been entered
    if (!$_POST['name']) {
        $errName = 'Please enter your name';
    }

    // Check if email has been entered and is valid
    if (!$_POST['email'] || !filter_var($_POST['email'], FILTER_VALIDATE_EMAIL)) {
        $errEmail = 'Please enter a valid email address';
    }

    //Check if message has been entered
    if (!$_POST['message']) {
        $errMessage = 'Please enter your message';
    }
    //Check if simple anti-bot test is correct
    if ($human !== 4) {
        $errHuman = 'Your anti-spam is incorrect';
    }
    // If there are no errors, send the email
    if (!$errName && !$errEmail && !$errMessage && !$errHuman) {
        if (mail ($to, $subject, $body, $from)) {
            print '<div class="alert alert-success">Thank You! I will be in touch</div>';
            exit();
        } 
        else {
            print '<div class="alert alert-danger">Sorry there was an error sending your message. Please try again later.</div>';
            exit();
        }
    }
}

?>

Answer 1

试试这个。我没有测试过，但这应该像魅力一样。如果您仍然遇到错误，请发布。

if (isset ($_POST['name'])){ //RUN ONLY IF name IS SET

$name = $_POST['name'];
$email = $_POST['email'];
$phone = $_POST['phone'];
$message = $_POST['message'];
$human = intval($_POST['human']);

 // Error handling for missing data
 if ((!$name) || (!$email) || (!$phone) || (!$message) || ($human !== 4)){ 
 $result = '<div class="alert alert-danger"><i class="glyphicon glyphicon-warning-sign"></i> <strong>ERROR:</strong> You did not submit the following required information:</div>';

     if(!$name){ 
       $result .= '<div class="alert alert-danger"><strong>Please enter your name</strong></div>';
     }else if(!$_POST['email'] || !filter_var($_POST['email'], FILTER_VALIDATE_EMAIL)){ 
       $result .= '<div class="alert alert-danger"><strong>Please enter a valid email address</strong></div>';
     }else if(!$phone){ 
       $result .= '<div class="alert alert-danger"><strong>Please enter a phone number</strong></div>';
     }else if(!$message){ 
       $result .= '<div class="alert alert-danger"><strong>Please enter your message</strong></div>';
     }else if($human !== 4){ 
       $result .= '<div class="alert alert-danger"><strong>Please correct your addition</strong></div>';
     }
 } else { // Error handling is ended, process form and send email


$from = 'From: example';
$to = 'example@gmail.com';
$subject = 'Message from X';

$body ="From: $name\n E-Mail: $email\n Phone: $phone\n Message:\n $message";

mail($to, $subject, $body, $from);

   print '<div class="alert alert-success">Thank You! I will be in touch</div>';
   exit();

   } // Close else after duplication checks

} else { // if the form is not posted with variables, place default empty variables so no warnings or errors show

  $name = "";
  $email = "";
  $phone = "";
  $message = "";
  $human = "";
  $result = "";

  print '<div class="alert alert-danger">Sorry there was an error sending your message. Please try again later.</div>';
  exit();
}

Answer 2

您的PHP文件中没有print或echo语句...

将echo $result添加到PHP文件的末尾以查看结果

Answer 3

更改您的成功代码。这将在页面重新加载时打印您的成功或错误消息。

    if (!$errName && !$errEmail && !$errMessage && !$errHuman) {
        if (mail ($to, $subject, $body, $from)) {
            print '<div class="alert alert-success">Thank You! I will be in touch</div>';
            exit();
        } else {
            print '<div class="alert alert-danger">Sorry there was an error sending your message. Please try again later.</div>';
            exit();
        }
    }

Answer 4

确定是否设置了变量：

 if (!isset($errName) && !isset($errEmail) && !isset($errMessage) && !isset($errHuman)) {
        if (mail ($to, $subject, $body, $from)) {
            $result='í<div class="alert alert-success">Thank You! I will be in touch</div>';
        } else {
            $result='<div class="alert alert-danger">Sorry there was an error sending your message. Please try again later.</div>';
        }
    }
    if(isset($result)){
    echo $result;}

输入表单不解析错误并在提交时显示空白页面

4 个答案: