Question

我想根据年份将项目组合在一起。它将显示在类似

的表格中

 2010
   -item 1 
   -item 2 
   -item 3
 2009
   -item 4
   -item 5 
   -item 6

我如何使用php和mysql做到这一点？

Answer 1

SELECT year(datefield) as year, name_of_item
FROM yourtable
ORDER BY year, name_of_item

将是基本的查询结构，然后

$first = true;
$previous_year = null;

echo "<ul>";
while($row = mysql_fetch(...)) {
    if ($previous_year != $row['year']) {
       ... got a new year, start a new list
       if (!$first) {
            echo "</ul>";
       }
       $first = false
       $previous_year = $row['year']
    }
    echo "<li>", $row['name_of_item'], "</li>"
}
echo "</ul>"

Answer 2

您可以将每个数据库行放入一个关联数组中，以year作为键，然后迭代数组以构建列表

  $yearItems = array();
  while ($row = mysql_fetch_assoc($result)) {
    $yearItems[$row['year']][] = $row;
  }

  foreach($yearItems as $year=>$items)
  {
    echo $year;

    echo "<ul>";
    foreach($items as $item)
    {
      echo "<li>$item</li>";
    }
    echo "</ul>";
  }

如何从列中获取唯一值并使用其他列中的值对它们进行分组？

2 个答案: