在矩阵中查找元素的邻居？

Question

例如，矩阵3x3

'0 1 2
 3 4 5
 6 7 8'

元素0的

是1,3,4。

Answer 1

# 2dMatrix: Your matrix
# x: x-coordinate of the element for which you're searching for neighbors 
# y: y-coordinate of the element for which you're searching for neighbors
def nearest_elements_2dMatrix(2dMatrix, x,y):
    upleft = 2dMatrix[x-1][y-1] if (x-1 >= 0 and y-1>=0) else None
    downleft = 2dMatrix[x-1][y+1] if (x-1 >= 0 and y+1 < len(2dMatrix)) else None
    left = 2dMatrix[x-1][y] if x-1 >= 0 else None
    upright = 2dMatrix[x+1][y-1] if (x+1 < len(2dMatrix[0]) and y-1>=0) else None
    right= 2dMatrix[x+1][y] if x+1 < len(2dMatrix[0]) else None
    downright = 2dMatrix[x+1][y+1] if (x+1 < len(2dMatrix[0]) and y+1 < len(2dMatrix)) else None
    above= 2dMatrix[x][y-1] if if y-1 >= 0 else None
    below= 2dMatrix[x][y+1] if if y+1 < len(2dMatrix) else None
    return [upleft, downleft, left, upright, right, downright, above, below]