我正在报告我之前遇到过相同问题的问题,但解决了here is the link to question,
在这里,我遇到了同样的问题,这里的变化不大,我还要求分区
CASE WHEN MP.PT = 'OPD' THEN COUNT(MP.YN) OVER (PARTITION BY MP.PT,mp.tti ORDER BY mp.tti) END AS OPD,
CASE WHEN MP.PT = 'IPD' THEN COUNT(MP.YN) OVER (PARTITION BY MP.PT,mp.tti ORDER BY mp.tti) END AS IPD,
CASE WHEN MP.PT = 'A&E' THEN COUNT(MP.YN) OVER (PARTITION BY MP.PT,mp.tti ORDER BY mp.tti) END AS EAC
结果应与单个选择的一部分位于同一行,但它出现在多行而不会聚合
答案 0 :(得分:1)
试试这个:
SUM(IIF(MP.PT = 'OPD', 1, 0)) OVER (PARTITION BY mp.tti) AS OPD,
SUM(IIF(MP.PT = 'IPD', 1, 0)) OVER (PARTITION BY mp.tti) AS IPD,
SUM(IIF(MP.PT = 'A&E', 1, 0)) OVER (PARTITION BY mp.tti) AS EAC