Question

所以我创建了一些屏幕并为它们添加了一些属性（布局，按钮，名称等），但一切都在kivy文件上。现在，我想在python主文件中创建一个函数，它将在短时间后将我从开始屏幕带到下一个屏幕。虽然没有我不得不将所有内容从kivy文件移动到python文件，但似乎没有任何工作。有什么想法吗？

的.py

from kivy.app import App
from kivy.uix.screenmanager import ScreenManager, Screen
from kivy.lang import Builder
from kivy.uix.image import Image
from kivy.uix.label import Label
from kivy.uix.behaviors import ButtonBehavior


class MainScreen(Screen):
    pass

class AnotherScreen(Screen):
    pass


class AndAnotherScreen(Screen):
    pass


class ScreenManagement(ScreenManager):
    pass

class BackgroundLabel(Label):
    pass

class CompanyImage(Image):
    pass

class LoadingScreen(Screen):
    def __init__(self, **kwargs):
        super(LoadingScreen, self).__init__(**kwargs)
    def ChangeScreen(self):
        ScreenManager().current = MainScreen().name



presentation = Builder.load_file("tsalapp.kv")


class MainApp(App):
    def build(self):
        return presentation


if __name__ == "__main__":
    MainApp().run()

.kv

#: import FadeTransition kivy.uix.screenmanager.FadeTransition
#:import Clock kivy.clock.Clock
#: import Color kivy.graphics
#: import Rectangle kivy.graphics

ScreenManagement:
    transition: FadeTransition()
    LoadingScreen:
    MainScreen:
    AnotherScreen:
    AndAnotherScreen:

<BackgroundLabel>:
    background_color: 30,144,255,1
    canvas.before:
        Color:
            rgba: self.background_color
        Rectangle:
            pos: self.pos
            size: self.size

<LoadingScreen>:
    name: "main"
    id: "yolo"
    on_enter: Clock.schedule_once(none, 3)
    #app.root.current: "menu"
    Image:
        source: 'Untitled.png'
        height: root.height
        width: root.width
        allow_stretch: True
        keep_ratio: False
    AnchorLayout:
        Label:
            text: "Tsala Inc."
            anchor_x: 'center'
            anchor_y: 'center'
            font_size: root.height/15





<MainScreen>:
    name: "menu"
    id: "swag"
    BoxLayout:
        orientation: "vertical"
        Button:
            text: "Next Page"
            background_color: 1,1,4,1
            size_hint: (0.5, 0.5)
            on_release:
                app.root.current= "Another Screen"
        Button:
            text: "Previous Page"
            background_color: 1,4,1,1
            size_hint: (0.5, 0.5)
            on_release:
                app.root.current= "And Another Screen"

<AnotherScreen>:
    name: "Another Screen"
    GridLayout:
        cols: 2
        Button:
            text: "Previous Page"
            background_color: 0,0,1,1
            size_hint: (0.25,1)
            on_release:
                app.root.current = "menu"
        Button:
            text: "Exit"
            background_color: 1,0,0,1
            size_hint: (0.25, 1)
            on_release:
                exit()

<AndAnotherScreen>:
    name: "And Another Screen"
    BoxLayout:
        orientation: "vertical"
        Button:
            text: "Next Page"
            background_color: 1,1,4,1
            size_hint: (0.5, 0.5)
            on_release:
                app.root.current= "menu"
        Button:
            text: "Nextest Page"
            background_color: 1,4,1,1
            size_hint: (0.5, 0.5)
            on_release:
                app.root.current= "Another Screen"

Answer 1

首先，我建议为screenmanager创建一个全局变量，或者在MainApp中将screenmanager作为类属性放置，并为屏幕创建一个列表或字典：

class MyApp(App):

    sm = ScreenManager() # screenmanager
    screens = {} # dictionary for the screens, I prefer dictionary because string indexes are more convenient

然后在构建方法中，您可以创建所需的所有屏幕，并将screenmanager作为根窗口小部件返回：

class MyApp(App):

    sm = ScreenManager() # screenmanager
    screens = {} # dictionary for the screens, I prefer dictionary because string indexes are more convenient

    def build(self):
        self.__create_screens()
        MyApp.sm.add_widget(MyApp.screens['main_screen'])
        return MyApp.sm

    def __create_screens(self):
        MyApp.screens['main_screen'] = MainScreen(name='mainscreen')
        MyApp.screens['another_screen'] = AnotherScreen(name='another_screen')
        MyApp.screens['and_another_screen'] = AndAnotherScreen(name='and_another_screen')

现在，您可以使用switch_to方法轻松切换应用程序的屏幕：

MyApp.sm.switch_to(MyApp.screens['another_screen'], direction='left', duration=1)

.py文件与.kv文件交互

1 个答案: