我使用django 1.11进行编程,现在我在post_list.html中有以下脚本
{% with lang={{request.LANGUAGE_CODE}} %}
{% endwith %}
<p>
{% if lang == 'zh-CN' %} {{object.category.name_zh_CN}} {% else %} {{object.category.name}} {% endif %}
</p>
&#13;
但我实际上无法得到以下错误消息,请帮忙。谢谢。
TemplateSyntaxError at /adv/australia-strategic/
Could not parse the remainder: '{{request.LANGUAGE_CODE}}' from '{{request.LANGUAGE_CODE}}'
Request Method: GET
Request URL: http://localhost:8030/adv/australia-strategic/
Django Version: 1.11.6
Exception Type: TemplateSyntaxError
Exception Value:
Could not parse the remainder: '{{request.LANGUAGE_CODE}}' from '{{request.LANGUAGE_CODE}}'
Exception Location: /Users/wzy/anaconda2/envs/python36/lib/python3.6/site-packages/django/template/base.py in __init__, line 700
Python Executable: /Users/wzy/anaconda2/envs/python36/bin/python
Python Version: 3.6.3
Python Path:
['/Users/wzy/expo3/expo',
'/Users/wzy/anaconda2/envs/python36/lib/python36.zip',
'/Users/wzy/anaconda2/envs/python36/lib/python3.6',
'/Users/wzy/anaconda2/envs/python36/lib/python3.6/lib-dynload',
'/Users/wzy/anaconda2/envs/python36/lib/python3.6/site-packages',
'/Users/wzy/expo3/expo']
&#13;
答案 0 :(得分:1)
{% %}
中不需要双花括号,而只需使用变量:
{% with lang=request.LANGUAGE_CODE %}
{% endwith %}
<p>
{% if lang == 'zh-CN' %} {{object.category.name_zh_CN}} {% else %} {{object.category.name}} {% endif %}
</p>
中详细了解相关信息
答案 1 :(得分:1)
{% with lang=request.LANGUAGE_CODE %}
<p>
{% if lang == 'zh-CN' %} {{object.category.name_zh_CN}} {% else %} {{object.category.name}} {% endif %}
</p>
{% endwith %}
但你可以简化它:
<p>
{% if request.LANGUAGE_CODE == 'zh-CN' %} {{object.category.name_zh_CN}} {% else %} {{object.category.name}} {% endif %}
</p>