Question

var_dump显示以下内容，我想循环显示此内容并希望显示所有电子邮件

array(85) {
  ["attributes"]=>
  array(2) {
    ["type"]=>
    string(7) "Contact"
    ["url"]=>
    string(56) "/services/data/v20.0/sobjects/Contact/000002HQRBYAA5"
  }
  ["Id"]=>
  string(18) "0030002HQRBYAA5"
  ["IsDeleted"]=>
  bool(false)
  ["Email"]=>
  string(28) "t@stics.com"

}
array(85) {
  ["attributes"]=>
  array(2) {
    ["type"]=>
    string(7) "Contact"
    ["url"]=>
    string(56) "/services/data/v20.0/sobjects/Contact/0002HQRBTAA5"
  }
  ["Id"]=>
  string(18) "0000002HQRBTAA5"
  ["IsDeleted"]=>
  bool(false)
  ["Email"]=>
  string(35) "test@gmail.com"

}

我在PHP中尝试的是这个

$accID="3234234";
$url1 = "$instance_url/services/data/v20.0/sobjects/Contact/$accID";
$curl1 = curl_init($url1);

curl_setopt($curl1, CURLOPT_HEADER, false);
curl_setopt($curl1, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl1, CURLOPT_HTTPHEADER,
array("Authorization: OAuth $access_token"));
$json_response1 = curl_exec($curl1);


$status = curl_getinfo($curl1, CURLINFO_HTTP_CODE);
curl_close($curl1);


$objContact = json_decode($json_response1, TRUE);
//var_dump($objContact);

for($i=0; $i<count($objContact['attributes']); $i++) {
    echo "Contact email is " . $objContact['Email'][$i] . "<BR>";

}

Answer 1

你有一个数组数组，每个数组都有一个foreach($objContact as $data){ echo $data['Email'] . '<br>'; }键，所以简单地说：

export class MyDtoDataSource extends DataSource<IMyDto> {
      private _filterChange = new BehaviorSubject('');
      public get filter(): string { return this._filterChange.value; }
      public set filter(filter: string) { this._filterChange.next(filter); }

      constructor(private _apiService: ApiService) {
          super()
      }

      connect(): Observable<IMyDto[]> {

          const displayDataChanges = [
              this._apiService.getMyDtos(),
              this._filterChange,
          ];

          return Observable
          .merge(...displayDataChanges)
          .map((dtos: IMyDto[]) => dtos.filter(dto => dto.categories.map(i => i.name).includes(this.filter)));
      }

  disconnect() {
  }
}

Answer 2

请尝试foreach循环：

foreach($objContact as $contact)
{
    echo "Contact email is " . $contact['Email'] . "<br>";
}

或与for循环类似：

for($i=0; $i<count($objContact); $i++)
{
    echo "Contact email is " . $objContact[$i]['Email'] . "<BR>";
}

PHP - 无法从此Json响应中提取电子邮件

2 个答案: