Question

我试图使用JavaScript从休息服务器解析Json响应并显示数据。其余的服务器工作正常，我无法解析数据。我看了几十个例子，根据我的理解，代码看起来很好。这是我第一次尝试学习Ajax，如果我解决这个问题，我可以继续我的项目。

这是回复

{"id":"1","author":"Bill Burke","title":"RESTful Java with JAX-RS","year":"2009"}

这是服务器

@Path("/books") // JAX-RS annotation
public class BookResource {

@GET // JAX-RS annotation
@Produces({ MediaType.APPLICATION_XML, MediaType.APPLICATION_JSON, MediaType.TEXT_XML })
@Path("/{bookId}")
public Book getBook(@PathParam("bookId") String id) {
    return BookDao.instance.getBook(Integer.parseInt(id));
}
}

这是客户

<!DOCTYPE html>
<html>
<head>
<title>Form to create a new resource</title>

<script type="text/javascript">

function getHTTPObject() {
    var xhr = false;
    if (window.XMLHttpRequest) {
        xhr = new XMLHttpRequest();
    } else if (window.ActiveXObject) {
        try {
            xhr = new ActiveXObject("Msxml2.XMLHTTP");
        } catch (e) {
            try {
                xhr = new ActiveXObject("Microsoft.XMLHTTP");
            } catch (e) {
                xhr = false;
            }
        }
    }
    return xhr;
}

function grabFile(file) {
    var request = getHTTPObject();
    if (request) {
        request.onreadystatechange = function() {
            parseJ(request);
        };
        request.open("GET", file, true);
        request.send(null);
    }
}

function parseJ(request) {
    if (request.readyState == 4) {
        if (request.status == 200 || request.status == 304) {

            var obj = JSON.parse(request.responseText);
            document.getElementById("details").innerHTML = obj.id + " " + obj.author + " "
                    + obj.title + " " + obj.year;

        }
    }
}
</script>
</head>
<body>

<a
    href="http://localhost:8080/Distributed_REST_booksServer/rest/books/1"
    onclick="grabFile(this.href); return false;">Book 1</a>
<br>
<div id="details"></div>
</body>
</html>

html console error

html console error after modification

Answer 1

您的服务器正在返回XML，尝试将其强制为JSON，并且可能会向客户端的请求添加接受标头。

无法从休息服务器

1 个答案: