Question

我需要一个TSQL版本的group_concat Simmilar对该示例发现了here：

Policy   Destination   ID
-------------------------
PolA     DestA         1    
PolA     DestA         2    
PolB     DestB         3     
PolB     DestB         4    
PolC     DestC         5
PolC     DestC         6
PolC     DestD         7

输出应如下所示：

PolA   DestA   1,2
PolB   DestB   3,4
PolC   DestC   5,6
PolC   DestD   7

分组是前两列的唯一性，然后是第三列的连接输出。

我找到了this link，但它只考虑了2列

任何帮助都将不胜感激。

Answer 1

在MSSQL Synax中：

SELECT Policy, Destination, STRING_AGG ( [ID], ',' ) IDs
FROM Table

Answer 2

你可以试试这个：

SELECT G.Policy, G.Destination,
    stuff(
    (select cast(',' as varchar(max)) + U.ID
    from yourtable U
    WHERE U.Policy = G.Policy and U.Destination = G.Destination
    order by U.Policy
    for xml path('')
    ), 1, 1, '') AS IDs
FROM yourtable G group BY G.Policy, G.Destination

Answer 3

我只是为您创建PolA示例表，只需将CTE替换为您的表格，请尝试以下操作：

WITH ABC
as
(
select   'PolA' as Policy,'DestA' as Destination,'1' as ID  
UNION ALL 
select 'PolA','DestA','2'
)

SELECT Policy, Destination,
 STUFF((SELECT ',' + A.ID FROM ABC as A WHERE A.Policy = B.Policy FOR XML PATH('')),1,1,'') as ID
FROM ABC as B
GROUP BY B.policy, B.Destination

SQL Concatenate和group

输出应如下所示：

3 个答案: