Question

我的第一个问题在这里！

我正在使用python和flask开发webservices。 Neo4j是我的后端，我想APIfy。

我在图形数据库上运行匹配查询，并希望返回一个json对象。以下是代码。

from flask import Flask, jsonify
from neo4j.v1 import GraphDatabase

app = Flask(__name__)

uri = "bolt://localhost:7687"
driver = GraphDatabase.driver(uri, auth=(user, pass))

@app.route('/')
def com_relations():
    with driver.session() as session:
        with session.begin_transaction() as tx:
            return jsonify(tx.run("MATCH (company:Company)-[]->(c) where c.name is not null "
                             "RETURN company.name, c.name"))

        session.close()

但是我在运行应用程序时遇到错误。

TypeError: Object of type 'BoltStatementResult' is not JSON serializable

我理解错误，我想知道如何从neo4j jsonify我的语句结果。请帮忙。

Answer 1

问题是查询的结果是StatementResult object，无法“序列化”。所以你需要先准备这样的结果：

from flask import Flask, jsonify
from neo4j.v1 import GraphDatabase

app = Flask(__name__)

uri = "bolt://localhost:7687"
driver = GraphDatabase.driver(uri, auth=(user, pass))

@app.route('/')
def com_relations():
    with driver.session() as session:
        with session.begin_transaction() as tx:
            results = (tx.run("MATCH (company:Company)-[]->(c) where c.name is not null"
                              "RETURN company.name, c.name"))    
        session.close()
        records = []
        for record in results:
            records.append({"company.name": record["company.name"],
                            "name": record["c.name"]})
        return jsonify(records)

Answer 2

您也可以更改查询以获取JSON格式。

"MATCH (company:Company)-[]->(c) where c.name is not null RETURN COLLECT({company:company.name, name:c.name}) AS jsonOutput"

jsonify bolt statementresult

2 个答案: