Question

我正在使用IEnumerator作为可以重置的计时器。我有一个航点系统设置，你可以在这里观察一个航路点n秒钟传送到它。我使用IEnumerator来控制那个时间，并阻止意外的远距传送。它工作得很好，但是如果我注视任何一个光线投射项目，它会在某个地方与逻辑混淆，你必须看一下然后重新看一个航点再次启动它。这个失败也会在我的航点的所有实例中运行，看一眼并远视并看另一个将无法传送。我正在使用GVR激光指针和来自GVR的GVR Reticle构建1.70（1.100无法构建）。

代码：

using System.Collections;
using System.Collections.Generic;
using UnityEngine;

public class Gaze_Waypoints : MonoBehaviour {

public int gazeTime = 3; //the amount of time needed to look to teleport
public GameObject playerCam; //the players camera
private Vector3 waypointPosition; //the position of the current waypoint
private Vector3 playerCamPosition; //the current position of the players camera used for height information
private IEnumerator waypointEnumerator; //my co-routine
private bool startCoRoutine; //is the co-routine running

void Start () {
    waypointPosition = transform.position;  //get the position of the owners waypoint
    waypointEnumerator = waypointTimerEvent (); //set the ienumerator to the relevant function below
    startCoRoutine = true; //testing this out as true or false
}

void Update () {
    playerCamPosition = playerCam.transform.position; //keep track of the players camera, mainly for height info
}

// when I gaze a waypoint
public void PointerEnter() {
    Debug.Log("I entered.");
    if (startCoRoutine) {
        StartCoroutine (waypointEnumerator);
    } else {
        StopCoroutine (waypointEnumerator);
    }
    startCoRoutine = !startCoRoutine;
}

// when I look away
public void PointerExit() {
    Debug.Log("I exited.");
    StopCoroutine (waypointEnumerator);
}

// if I look for 3 seconds teleport the user, if I look away reset the timer
IEnumerator waypointTimerEvent() {
    yield return new WaitForSeconds (gazeTime);
    playerCam.transform.position = new Vector3 (waypointPosition.x, waypointPosition.y + playerCamPosition.y, waypointPosition.z);
    StartCoroutine(waypointEnumerator);
}
}

Answer 1

查看MonoBehaviour.StartCoroutine

的不同调用

public Coroutine StartCoroutine（IEnumerator例程）;
public Coroutine StartCoroutine（string methodName，object value = null）;

案例1. - 未经测试但很明显你必须在协程中使用循环，如

4278255873
-16711423

案例2. - 经过修改但经过测试确定

while (true){
    yield return new WaitForSeconds(waitTime);
    debug.Log("WaitAndPrint");
}

Unity GVR使用IEnumerator

1 个答案: