我迷失在文档中,真的忘记了要做什么。我认为解决方案是使用环境但我无法弄清楚即使我觉得它并不复杂。
这是一个使用两个类的简单示例:
Person <- setClass(
Class = "Person",
slots = c(name = "character",
id = "numeric",
age = "numeric"));
PersonList <- setClass(
Class = "PersonList",
slots = c(datasetList = "list"));
以下是对象创建:
mary <- new("Person", name = "Mary", id = 1, age = 35);
peter <- new("Person", name = "Peter", id = 2, age = 39);
john <- new("Person", name = "John", id = 3, age = 25);
employees <- new("PersonList", datasetList = list(mary, peter, john));
然后我定义了两个设置年龄和id的方法,以及一个子设置PersonList的方法:
setGeneric(name = "setAge<-", def = function(theObject, value){standardGeneric("setAge<-");});
setGeneric(name = "setid<-", def = function(theObject, value){standardGeneric("setid<-");});
setReplaceMethod(
f = "setAge",
signature = "Person",
definition = function(theObject, value){
theObject@age <- value;
return(theObject);
});
setReplaceMethod(
f = "setid",
signature = "Person",
definition = function(theObject, value){
theObject@id <- value;
return(theObject);
});
setMethod(
f = "[[",
signature = c("PersonList", "ANY", "ANY"),
definition = function(x, i, j, ...){
return(x@datasetList[[i]]);
});
现在问题在于:
> setAge(employees[[1]]) <-56
Error in `[[<-`(`*tmp*`, 1, value = new("Person",
name = "Mary", id = 1, :
[[<- defined for objects of type "S4" only for subclasses of environment
如果我理解正确,我必须使用环境来获得类似的东西:
setMethod(
f = "[[<-",
signature = c("PersonList", "ANY", "ANY"),
definition = function(x, i, j, ...){
if environment is setid return(setId(x[[i]]))
if environment is setAge return(setAge(x[[i]]))
});
通过文档,这变得非常复杂。任何人都可以给我一个如何做到这一点的提示吗?
非常感谢。
答案 0 :(得分:1)
您只需要为[[<-
课程定义PersonList
:
setMethod(
f = "[[<-",
signature = c("PersonList"),
definition=function(x,i,j,value) {
x@datasetList[[i]] <- value
return(x)
})
那么你的代码应该可行。但是,您可以添加一些代码来检查完整性。与inherits(value, "Person")
和missing(j)
一样。