Question

我试图比较NLTK的Stanford Parser的结果，但我不知道为什么当我与stanford parser进行比较时，我会得到不同的结果我已经检查过相关问题，但这对我没什么帮助。

stan_dep_parser = StanfordDependencyParser() # stanford parser from NLTK 
dependency_parser =stan_dep_parser.raw_parse("Four men died in an accident")
dep = dependency_parser.next()
for triple in dep.triples():
   print triple[1],"(",triple[0][0],", ",triple[2][0],")"

当前输出：

nsubj ( died ,  men )
nummod ( men ,  Four )
nmod ( died ,  accident )
case ( accident ,  in )
det ( accident ,  an )

根据stanford parser的预期输出：

nummod(men-2, Four-1)
nsubj(died-3, men-2)
root(ROOT-0, died-3)
case(accident-6, in-4)
det(accident-6, an-5)
nmod(died-3, accident-6)

NLTK版本：3.2.4 Stanford Parser：stanford-parser-3.8.0-models

Answer 1

我自己解决了问题：

我找到了＆＃39; root＆＃39;或者＆＃39; head＆＃39;句子：

final_dependency = []
sentence = "Four men died in an accident"
dependency_tree = StanfordDependencyParser()
dependency_parser = dependency_tree.raw_parse(sentence)
parsetree = list(dependency_parser)[0]
for k in parsetree.nodes.values():
       if k["head"] == 0:
            final_dependency.append(str(k["rel"])  + "(" + "Root" + "-" 
                + str(k["head"]) + "," + str(k["word"]) + "-" + str(k["address"]) + ")" )

然后我用简单的字符串操作在预期输出中添加带有单词的数字，因为数字是句子中每个单词的索引。

使用NLTK的Stanford Parser的依赖树结果与Stanford Parser不匹配

1 个答案: