Question

我是Python3编码的新手，我在这里遇到了问题。在第14行，我打算通过打印结束这个程序＆＃34;谢谢！再见＆＃34;在你回答的部分＆＃34; n＆＃34;到＆＃34;再试一次？＆＃34;。然而，事实证明，即使我已插入＆＃34; break＆＃34;我也会重新开始。在它下面。现在，我能提出的唯一解决方案是用sys.exit(0)结束整个程序，但我不认为它是一个理想的解决方案，因为它只会关闭整个程序。

import sys
while True:

x=int(input("Enter the coins you expected="))
f=int(input("Enter first coin="))

while f!=1 and f!=5 and f!=10 and f!=25:
   print("invalid number")
   f=int(input("Enter first coin="))

if x>f:
    while x>f:
        n=input("Enter next coin=")
        if not n:
            print("Sorry-you only entered",f,"cents")
            again=input("Try again (y/n)?=")
            if again=="y":
                True
            elif again=="n":
                print("Thank you, goodbye!")
                sys.exit(0)
            break

        while int(n)!=1 and int(n)!=5 and int(n)!=10 and int(n)!=25:
            print("invalid number")
            n=input("Enter next coin=")
        f=f+int(n)

Answer 1

用以下代码替换整个代码：

import sys

Stay = True

while Stay:

    x = int(input("Enter the coins you expected = "))
    f = int(input("Enter first coin = "))

    while f != 1 and f != 5 and f != 10 and f != 25:
        f = int(input("Invalid number entered./nEnter first coin = "))

    while x > f and Stay:

        n = input("Enter next coin = ")

        if not n:

            print("Sorry, you only entered " + str(f) + " cents")
            again = input("Try again (y/n)?=")

            if again == "n":
                print("Thank you, goodbye!")
                Stay = False

        if Stay:

            n = int(n)
            while n != 1 and n != 5 and n != 10 and n != 25:
                print("Invalid number entered.")
                n = int(input("Enter next coin = "))
            f += n

我使代码更具可读性，并使用布尔标志（Stay）修复了问题。这基本上意味着该程序在Stay为True时运行，而Stay在用户输入False后变为'n'。

如何结束程序（Python）？

1 个答案: