我使用tensorflow来构建卷积神经网络。给定一个形状的张量(无,16,16,4,192)我想执行一个转置卷积,导致形状(无,32,32,7,192)。
过滤器大小[2,2,4,192,192]和步幅[2,2,1,1,1]会产生我想要的输出形状吗?
答案 0 :(得分:1)
是的,你几乎是对的。
一个小的修正是tf.nn.conv3d_transpose
期望NCDHW
或NDHWC
输入格式(您的显示为NHWDC
),滤镜形状预计为{{1} }。这会影响[depth, height, width, output_channels, in_channels]
和filter
:
stride
哪个输出:
# Original format: NHWDC.
original = tf.placeholder(dtype=tf.float32, shape=[None, 16, 16, 4, 192])
print original.shape
# Convert to NDHWC format.
input = tf.reshape(original, shape=[-1, 4, 16, 16, 192])
print input.shape
# input shape: [batch, depth, height, width, in_channels].
# filter shape: [depth, height, width, output_channels, in_channels].
# output shape: [batch, depth, height, width, output_channels].
filter = tf.get_variable('filter', shape=[4, 2, 2, 192, 192], dtype=tf.float32)
conv = tf.nn.conv3d_transpose(input,
filter=filter,
output_shape=[-1, 7, 32, 32, 192],
strides=[1, 1, 2, 2, 1],
padding='SAME')
print conv.shape
final = tf.reshape(conv, shape=[-1, 32, 32, 7, 192])
print final.shape