REGEX_SUBSTR Redshift

Question

我需要从广告系列代码中提取日期和月份，但我的查询只返回NULL值。日期和月份始终遵循＆＃39; mmmdd＆＃39; （例如，aug23，sep12，oct09）虽然广告系列的总长度不同。

示例查询：

SELECT Campaign,
       Year,
       REGEXP_SUBSTR(campaign, '[a-z]{3}\d{2}') AS Month_Day

FROM GA_CAMPAIGN

样本表：

Campaign                                           | Year | Month_Day
TL-17-push-general-sep15septemberhighlights-0-0-0- | 17   | NULL
FA-17-stoke-aug09augusthighlights-0-0-0-0-0        | 17   | NULL

期望的输出：

Campaign                                           | Year | Month_Day
TL-17-push-general-sep15septemberhighlights-0-0-0- | 17   | sep15
FA-17-stoke-aug09augusthighlights-0-0-0-0-0        | 17   | aug09

提前谢谢！

Answer 1

\d无法正常工作。请尝试使用[0-9]。

WITH sample AS (
          SELECT 'TL-17-push-general-sep15septemberhighlights-0-0-0' campaign
UNION ALL SELECT 'FA-17-stoke-aug09augusthighlights-0-0-0-0-0'       campaign
)
SELECT campaign,
       REGEXP_SUBSTR(campaign, '[a-z]{3}[0-9]{2}') AS Month_Day
FROM sample
;
--                     campaign                      | month_day
-----------------------------------------------------+-----------
-- TL-17-push-general-sep15septemberhighlights-0-0-0 | sep15
-- FA-17-stoke-aug09augusthighlights-0-0-0-0-0       | aug09